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skelet666 [1.2K]
3 years ago
12

How can we use cyanobacteria as an energy source

Chemistry
1 answer:
mylen [45]3 years ago
4 0

Answer:

With a short life cycle, greenhouse gas fixation ability, and high lipid production capacity, we use cyanobacteria as an efficient biofuel platform. Carbon dioxide released by the burning of fossil fuel and industrial emissions can be captured and used by these organisms efficiently.

Explanation:

What do cyanobacteria use for energy production?

oxygenic photosynthesis

They commonly obtain their energy through oxygenic photosynthesis, which produces the oxygen gas in the atmosphere of Earth. The name cyanobacteria comes from their color (Greek: κυανός, romanized: kyanós, lit.

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3. A sample of carbon has a mass of
Sav [38]

- 34 {}^{15}

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8 0
3 years ago
Aluminum can react with oxygen gas to produce aluminum oxide (Al2O3). What type of reaction is this?
Pachacha [2.7K]

It's Synthesis, single replacement is incorrect.

6 0
4 years ago
The equilibrium constant in terms of pressure. Kp for the following process is 0.179 at 50 °C. It increases to 0.669 at 86 °C. C
Vikentia [17]

Answer:

a) ΔHvap=35.3395 kJ/mol

b) Tb=98.62 °C

Explanation:

Given the reaction:

C₇H₁₆ (l) ⇔ C₇H₁₆ (g)

Kp=P(C₇H₁₆) since the concentration ratio for a pure liquid is equal to 1.

When

T₁=50°C=323.15K ⇒P₁=0.179

T₂=86°C=359.15K ⇒P₂=0.669

The Clasius-Clapeyron equation is:

ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})

ln(\frac{0.669}{0.179}) =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{359.15K}-\frac{1}{323.15K})

1.3184 =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (-3.10186*10^{-4}K{^-1})

ΔHvap=35339.5 J/mol=35.3395 KJ/mol

Normal boiling point ⇒ P=1 atm

Hence, we find the normal boiling point where:

T₁=323.15K

P₁=0.179 atm

P₂=1 atm

ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})

ln(\frac{1atm}{0.179atm}) =-\frac{35339.5 J/mol}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{T_2}-\frac{1}{323.15K})

1.7203=-4250.34 (\frac{1}{T_2}-\frac{1}{323.15K})

T₂=371.77 K= 98.62 °C

5 0
3 years ago
Summarize the relationship between volume, temperature and pressure (use words like “inversely
Alinara [238K]

Answer:

P and V: inversely proportional

P and T: directly proportional

V and T: inversely proportional

Explanation:

For pressure and volume, as the volume goes up, meaning the container gets bigger, the pressure would go down. There would be more room in the container, so there would be less collisions between the molecules themselves and between the molecules and the container. This makes them inversely proportional.

For pressure and temperature, as the pressure goes up, there are more collisions, so the particles move faster. Temperature is the speed of the particles, so, since both pressure and temperature would go up at the same time, they are directly proportional.

For volume and temperature, this is similar to the PV relationship. As volume increases, there are less collisions between the particles. This means that the particles are going to move slower. Therefore, as volume goes up, temperature goes down, so they are inversely proportional.

Sorry this is super long, but I hope it fully explains the question for you! ☺

4 0
4 years ago
A
vodka [1.7K]
In my opinion the answer is identical
3 0
2 years ago
Read 2 more answers
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