1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
skelet666 [1.2K]
2 years ago
12

How can we use cyanobacteria as an energy source

Chemistry
1 answer:
mylen [45]2 years ago
4 0

Answer:

With a short life cycle, greenhouse gas fixation ability, and high lipid production capacity, we use cyanobacteria as an efficient biofuel platform. Carbon dioxide released by the burning of fossil fuel and industrial emissions can be captured and used by these organisms efficiently.

Explanation:

What do cyanobacteria use for energy production?

oxygenic photosynthesis

They commonly obtain their energy through oxygenic photosynthesis, which produces the oxygen gas in the atmosphere of Earth. The name cyanobacteria comes from their color (Greek: κυανός, romanized: kyanós, lit.

You might be interested in
Suppose you were to make a ring from a single strand of gold atoms. How many gold atoms would be required to make such a ring? H
Rudiy27
Let us assume that the ring is a size 7 ring, which has a circumference of 54.3 millimeters. Converting this to centimeters, the circumference of the ring is:

54.3 mm = 5.43 cm

Now, we determine the number of gold atoms that will be present in this:

5.43 / 1 x 10⁻⁹

There will be 5.43 x 10⁹ atoms


We now determine the number of moles this is by:

one mole = 6.02 x 10²³ atoms

Moles = 5.43 x 10⁹ / 6.02 x 10²³ 
Moles = 9.01 x 10⁻¹⁵ moles

The molar mass of gold is 197 g/mol

The mass is 9.01 x 10⁻¹⁵  * 197

The mass of the strand is 1.76 x 10⁻¹² grams
8 0
3 years ago
Read 2 more answers
Calculate [H3O+] and [OH−] for each of the following solutions at 25 ∘C given the pH. pH= 8.74, pH= 11.38, pH= 2.81
Gnom [1K]

Answer:

Explanation:

Given parameters;

pH  = 8.74

pH = 11.38

pH = 2.81

Unknown:

concentration of hydrogen ion and hydroxyl ion for each solution = ?

Solution

The pH of any solution is a convenient scale for measuring the hydrogen ion concentration of any solution.

It is graduated from 1 to 14

      pH = -log[H₃O⁺]

      pOH = -log[OH⁻]

 pH + pOH = 14

Now let us solve;

   pH = 8.74

             since  pH = -log[H₃O⁺]

                           8.74 =  -log[H₃O⁺]

                           [H₃O⁺] = 10⁻^{8.74}

                             [H₃O⁺]  = 1.82 x 10⁻⁹mol dm³

       pH + pOH = 14

                 pOH = 14 - 8.74

                  pOH = 5.26

                  pOH = -log[OH⁻]

                     5.26  = -log[OH⁻]

                     [OH⁻] = 10^{-5.26}

                      [OH⁻] = 5.5 x 10⁻⁶mol dm³

2.  pH = 11.38

             since  pH = -log[H₃O⁺]

                           11.38 =  -log[H₃O⁺]

                           [H₃O⁺] = 10⁻^{11.38}

                             [H₃O⁺]  = 4.17 x 10⁻¹² mol dm³

           pH + pOH = 14

                 pOH = 14 - 11.38

                  pOH = 2.62

                  pOH = -log[OH⁻]

                     2.62  = -log[OH⁻]

                     [OH⁻] = 10^{-2.62}

                      [OH⁻] =2.4 x 10⁻³mol dm³

3. pH = 2.81

             since  pH = -log[H₃O⁺]

                           2.81 =  -log[H₃O⁺]

                           [H₃O⁺] = 10⁻^{2.81}

                             [H₃O⁺]  = 1.55 x 10⁻³ mol dm³

           pH + pOH = 14

                 pOH = 14 - 2.81

                  pOH = 11.19

                  pOH = -log[OH⁻]

                     11.19  = -log[OH⁻]

                     [OH⁻] = 10^{-11.19}

                      [OH⁻] =6.46 x 10⁻¹²mol dm³

5 0
3 years ago
Consider the following data for five hypothetical elements: Q, W, X, Y, and Z. Rank the elements from most reactive to least rea
aleksley [76]

Answer:

Y Q W Z X

Explanations:

The most reactive element is the element that will displace an element from it compound . The most reactive element will replace the less reactive element in it compound.

Q+ + Y Reaction occurs

Since the reaction occurs the element Y which is more reactive displaced element Q from it compound.

Q+W+ Reaction occurs

The reaction occurs, that means element Q replaces element w from it compound. Element Q is therefore more reactive than element W.

W+Z+ Reaction occurs

The reaction also occurs . This is an indication that element W replaces element Z in it compound. This means element W is very reactive than element Z.

X+Z+ No reaction

There is no reaction here. This is an indication that element X is less reactive than element Z. This is why element X can't displace element Y in it compound.

4 0
3 years ago
Create and balance a chemical equation for the following statement.
m_a_m_a [10]
FeCl₂  +  2NH₄OH  →  Fe(OH)₂  +  2NH₄Cl
8 0
2 years ago
If the element is closer to the top of the table is it's ionization energy larger?
Ulleksa [173]

Answer:

21

Explanation:

3 0
2 years ago
Other questions:
  • A variation of the acetamidomalonate synthesis can be used to synthesize threonine. The process involves the following steps: Et
    9·1 answer
  • how many grams of bromine, br2, are required to react completely with 37.4 grams of aluminum chloride, AlCl3?
    6·1 answer
  • How many molecules (not moles) of nh3 are produced from 6.89×10−4 g of h2?
    5·1 answer
  • The total mass of the reactants is ________ the total mass of the products in a chemical reaction.
    7·1 answer
  • If you have 3.48 x 1023 formula units of Lead (II) Permanganate, what is its mass?
    10·1 answer
  • What type of wave is created by solar energy?
    12·1 answer
  • What is a force, provide an example
    13·1 answer
  • In Universe L , recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, qua
    13·1 answer
  • Electrons and the Periodic Table
    11·1 answer
  • You have to prepare a pH 5.00 buffer, and you have the following 0.10 M solutions available: HCOOH (pka=3.74), HCOONa, CH3COOH (
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!