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damaskus [11]
3 years ago
7

A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency

percentage of the machine
Physics
2 answers:
I am Lyosha [343]3 years ago
8 0

A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency percentage of the machine

Explanation:

A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency percentage of the machine

bekas [8.4K]3 years ago
6 0

Answer:

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<em>Join / LoginQuestionIn a lifting machine</em><em> </em><em>an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10000 N by a distance of 0.8 m</em><em> </em><em> Determine the velocity ratio and mechanical advantage</em>

<em> Determine the velocity ratio and mechanical advantageA</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20Easy</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in App</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolution</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolution</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by Toppr</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option is</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8m</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEd</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820VR=25</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820VR=25the load is 10,000N and effort=500N</em>

<em>MA=effortdloadd</em>

<em>MA=effortdloaddMA=50010000</em>

<em>MA=effortdloaddMA=50010000MA=20</em>

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Acceleration is equal to the initial velocity minus the final velocity, then divided by time.true or false
tatiyna

Almost true but not quite.

That would give you the negative of the actual acceleration.

It should be the other way around:

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Answer:

A. 181.24 N

Explanation:

The magnitude of hte electrostatic force between two charged objects is given by the equation

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In this problem, we have:

q_1=4.5\mu C=4.5\cdot 10^{-6}C is the magnitude of the 1st charge

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A) 181.24 N

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   Local action may be prevented by using pure zinc (which is not practical), by coating the zinc with mercury, or by adding a small percentage of mercury to the zinc during the manufacturing process. The treatment of the zinc with mercury is called amalgamating (mixing) the zinc. Since mercury is many times heavier than an equal volume of water, small particles of impurities weighing less than mercury will float to the surface of the mercury. The removal of these impurities from the zinc prevents local action. The mercury is not readily acted upon by the acid. When the cell is delivering current to a load, the mercury continues to act on the impurities in the zinc. This causes the impurities to leave the surface of the zinc electrode and float to the surface of the mercury. This process greatly increases the storage life of the cell.

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