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damaskus [11]
3 years ago
7

A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency

percentage of the machine
Physics
2 answers:
I am Lyosha [343]3 years ago
8 0

A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency percentage of the machine

Explanation:

A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency percentage of the machine

bekas [8.4K]3 years ago
6 0

Answer:

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<em>Join / LoginQuestionIn a lifting machine</em><em> </em><em>an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10000 N by a distance of 0.8 m</em><em> </em><em> Determine the velocity ratio and mechanical advantage</em>

<em> Determine the velocity ratio and mechanical advantageA</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20Easy</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in App</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolution</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolution</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by Toppr</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option is</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8m</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEd</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820VR=25</em>

<em> Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820VR=25the load is 10,000N and effort=500N</em>

<em>MA=effortdloadd</em>

<em>MA=effortdloaddMA=50010000</em>

<em>MA=effortdloaddMA=50010000MA=20</em>

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- The force of friction, which acts in the opposite direction (so, towards the left), of magnitude F_f = 5 N

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We can even calculate the magnitude of the acceleration. In fact, the mass of the crate is given by:

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