Given a volume of 1000. Cm^3 of an ideal gas at 300 k, what volume would iy occupy at a temperature of 600 k
1 answer:
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Answer:
1. 24375 N/C
2. 2925 V
Explanation:
d = 12 cm = 0.12 m
F = 3.9 x 10^-15 N
q = 1.6 x 10^-19 C
1. The relation between the electric field and the charge is given by
F = q E
So,
E = 24375 N/C
2. The potential difference and the electric field is related by the given relation.
V = E x d
where, V be the potential difference, E be the electric field strength and d be the distance between the electrodes.
By substituting the values, we get
V = 24375 x 0.12 = 2925 Volt
Answer:
Explanation:
We have here values from SI and English Units. I will convert the units to English Units.
We hace for the power P,
we have other values such and
(specific weight of the water), and 0.85 for \eta
We need to figure the flow rate of the water (V) out, that is,
Where is the turbine efficiency, at which is,
Replacing,
With this value (the target of this question) we can also calculate the mass flow rate of the waters,
through the density and the flow rate,
converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,