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miss Akunina [59]
3 years ago
10

The Gulf Stream off the east coast of the United States can flow at a rapid 3.9 m/s to the north. A ship in this current has a c

ruising speed of 11 m/s . The captain would like to reach land at a point due west from the current position.
Physics
2 answers:
alina1380 [7]3 years ago
5 0

Answer:

angle = 69.23 degrees west of south

Explanation:

The ship should go to the south at an equal rate as the water flows north so the velocities balance and the ship just move west.

As far as the water is concerned, the ship goes 3.9 m / s to the south, but much remains to the west. To find out that the triangle is drawing. 3.9 m/s point down side  and the hypotenuse is 11cos(angle) = \frac{adjacent}{hypotaneous}.

angle = cos^{-1}(\frac{adjacent}{hypotaneous})

angle = cos^{-1}(\frac{3.9}{11})

angle = 69.23 degrees west of south

Alex Ar [27]3 years ago
3 0

Answer:

72.54 degree west of south

Explanation:

flow = 3.9 m/s north

speed = 11 m/s

to find out

point due west from the current position

solution

we know here water is flowing north and ship must go south at an equal rate so that the velocities cancel and the ship just goes west

so it become like triangle with 3.3 point down and the hypotenuse is 11

so by triangle

hypotenuse ×cos(angle) = adjacent side

11 ×cos(angle) = 3.3

cos(angle) = 0.3

angle = 72.54 degree west of south

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<u>Explanation</u>:

<u>Given</u>:

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40 miles =  40 x 1.60934

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(B) If the car weighs 1.5 tons, what is its If the car weighs 1.5 tons, what is its kinetic energy in joules (Note: you will need to convert your velocity to m/s)? in joules (Note: you will need to convert your velocity to m/s)?

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1 ton = 1000 kg

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128.74  \times \frac{5}{18}

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Substituting the values,

K= \frac{1}{2}1500(35.75)^2

K= \frac{1}{2}1500(1278.06)

K= \frac{1500 \times (1278.06)}{2}

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K=958546.875 Joule---------------------------------------------(2)

(c)When the driver applies the brake, it takes 15 seconds to stop. How far does the car travel (in meters) while stopping

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S= ut+\frac{1}{2}at^2

Substituting the known values,

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Using the formula

v=u +at

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a = \frac{v - u}{t}

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s=536.25-267.75

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