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erma4kov [3.2K]
3 years ago
15

Water is being heated in a vertical piston-cylinder device. the piston has a mass of 20 kg and a cross-sectional area of 100 cm2

. if the local atmospheric pressure is 100 kpa, determine the temperature at which the water starts boiling.
Physics
1 answer:
sesenic [268]3 years ago
4 0
<span>Answer: We have pressure from the weight of the piston + atmospheric pressure acting on the gas pressure from the piston... P = F / area = mass x acceleration due to gravity / area P = (24 kg x 9.80 m/s²) / (90 cm² x (1m/100cm)²) = 26133 N/m² = 2.61x10^4 Pa = 26.1 kPa total pressure acting on the gas = 26+85 kPa = 111 kPa then.. via clausius clapeyron equation.. ln(P1 / P2) = (dHvap / R) x (1 / T2 - 1 / T1) and if I pick say.. the normal boiling point of water for P2, T2.. then... P1 = 111 kPa P2 = 101.325 kPa dHvap = 40680 J/mole R = 8.314 J/moleK T2 = 373.15 K T1 = ?? ---> T1 = 102.46°</span>
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if the vessel in the sample problem accelerates fir 1.00 min, what will its speed be after that minute ?
LUCKY_DIMON [66]

Answers:

a) 154.08 m/s=554.68 km/h

b) 108 m/s=388.8 km/h

Explanation:

<u>The complete question is written below: </u>

<u></u>

<em>In 1977 off the coast of Australia, the fastest speed by a vessel on the water was achieved. If this vessel were to undergo an average acceleration of 1.80 m/s^{2}, it would go from rest to its top speed in 85.6 s.  </em>

<em>a) What was the speed of the vessel? </em>

<em> </em>

<em>b) If the vessel in the sample problem accelerates for 1.00 min, what will its speed be after that minute? </em>

<em></em>

<em>Calculate the answers in both meters per second and kilometers per hour</em>

<em></em>

a) The average acceleration a_{av} is expressed as:

a_{av}=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{\Delta t} (1)

Where:

a_{av}=1.80 m/s^{2}

\Delta V is the variation of velocity in a given time \Delta t, which is the difference between the final velocity V and the initial velocity V_{o}=0 (because it starts from rest).

\Delta t=85.6 s

Isolating V from (1):

V=a_{av}\Delta t + V_{o} (2)

V=(1.80 m/s^{2})(85.6 s) + 0 m/s (3)

V=154.08 \frac{m}{s} (4)

If 1 km=1000m and 1 h=3600 s then:

V=154.08 \frac{m}{s}=554.68 \frac{km}{h} (4)

b) Now we need to find the final velocity when \Delta t=1 min=60 s:

<em></em>

V=(1.80 m/s^{2})(60 s) + 0 m/s (5)

V=108 \frac{m}{s}=388.8 \frac{km}{h} (6)

5 0
3 years ago
The curved section of a horizontal highway is a circular unbanked arc of radius 740m. If the coefficient of static friction betw
fiasKO [112]
Coefficient of static friction = tan(a) = 0.4
r = 740 m
g = 9.8 m/s²
v \:  =  \:  \sqrt{gr \tan( \alpha ) }
v = √(9.8 × 740 × 0.4) m/s
v ≈ 53.85908 m/s
6 0
4 years ago
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What can be the maximum value of the original kinetic energy of disk AA so as not to exceed the maximum allowed value of the the
timurjin [86]

The question is incomplete. The complete question is :

In your job as a mechanical engineer you are designing a flywheel and clutch-plate system. Disk A is made of a lighter material than disk B, and the moment of inertia of disk A about the shaft is one-third that of disk B. The moment of inertia of the shaft is negligible. With the clutch disconnected, A is brought up to an angular speed ?0; B is initially at rest. The accelerating torque is then removed from A, and A is coupled to B. (Ignore bearing friction.) The design specifications allow for a maximum of 2300 J of thermal energy to be developed when the connection is made. What can be the maximum value of the original kinetic energy of disk A so as not to exceed the maximum allowed value of the thermal energy?

Solution :

Let M.I. of disk A = $I_0$

So, M.I. of disk B =  $3I_0$

Angular velocity of A = $\omega_0$

So the kinetic energy of the disk A = $\frac{1}{2}I_0\omega^2$

After coupling, the angular velocity of both the disks will be equal to ω.

Angular momentum will be conserved.

So,

$I_0\omega_0 = I_0 \omega + 3I_0 \omega$

$I_0\omega_0 = 4I_0 \omega$

$\omega = \frac{\omega_0}{4}$

Now,

$K.E. = \frac{1}{2}I_0\omega^2+ \frac{1}{2}3I_0\omega^2$

$K.E. = \frac{1}{2}I_0\frac{\omega_0^2}{16}+ \frac{1}{2}3I_0\frac{\omega_0^2}{16}$

$K.E. = \frac{1}{2}I_0\omega_0^2 \left(\frac{1}{16}+\frac{3}{16}\right)$

$K.E. = \frac{1}{2}I_0\omega_0^2\times \frac{1}{4}$

$\Delta K = \frac{1}{2}I_0\omega_0^2 - \frac{1}{2}I_0\omega_0^2 \times \frac{1}{4} $

$2300=\frac{3}{4}\left(\frac{1}{2}I_0\omega_0^2\right)$

$\frac{1}{2}I_0\omega_0^2=2300 \times \frac{4}{3 } \ J $

Therefore, the maximum initial K.E. = 3066.67 J

3 0
3 years ago
Displacement vectors of 10 m west and 14 m west make a resultant vector that is _____.
Anastaziya [24]

For this case we can write each one of the vectors in the following way:

v1 = 10 i\\v2 = 14 i

This means that the x-axis is defined as positive towards the west.

Then, the resulting vector is:

v1 + v2 = 10i + 14i\\v1 + v2 = 24 i

Answer:

Displacement vectors of 10 m west and 14 m west make a resultant vector that is 24 m west

6 0
3 years ago
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Kristen is running half a marothon. By her tenth minute of running her breathing rate has increased from her resting rate. How a
astra-53 [7]

The question is incomplete as it does not have the options which are:

  1. They need more oxygen to function, so gas exchange needs to decrease.
  2. They need more oxygen to function, so gas exchange needs to increase.  
  3. They need more carbon dioxide to function, so gas exchange needs to increase.  
  4. They need more carbon dioxide to function, so gas exchange needs to decrease.

Answer:

They need more oxygen to function, so gas exchange needs to increase.  Explanation:

In the given question, Kristen is doing physical exercise for a long time as she is running in half marathon.

As a result of continuous running her breathing rate has increased because the physical exercise requires energy in the form of ATP.

The formation of ATP in the body is the result of the cellular respiration which takes place in the mitochondria which require oxygen and oxygen in the body is inhaled only through the breathing. So, more production of the ATP requires more oxygen and therefore more breathing.

Thus, the selected option is correct.

6 0
3 years ago
Read 2 more answers
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