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qaws [65]
3 years ago
8

PARALLEL PERPENDICULAR OR NEITHER

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0

Answer:

Parallel

Step-by-step explanation:

Using these points, we can determine that the equation is as follows:

Line B: y = -2/3x + 7/3

And since Line A has the same slope, it would make Line A's equations like this:

Line A: y = -2/3x - 11/3

This makes these equations Parallel to each other because they have the same slope with different y-intercepts.

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Stores often mark up items each year to cover inflation.
miv72 [106K]

Answer:

so you have $12.95. then you multiply it by 8% which gives you $13.986. Then you take 10% off of it, which gives you $12.5874.

3 0
3 years ago
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Please help it's urgent
dolphi86 [110]
X
1. 2x^2 - 8 = 2(x^2 - 4) = 2(x+2)(x-2)
2. 2x^2 + 8x + 6 = 2(x^2 + 4x + 3) = 2(x+3)(x+1)
3. 3n^2 + 9n -30 = 3(n^2 + 3n - 10) = 3(n+5)(n-2)

XII
1. x^2 + 2x + xy + 2y = x(x+2) + y(x+2) = (x+2)(x+y)
2. 3a^2 - 2b - 6a + ab = 3a^2 - 6a + ab - 2b = 3a(a - 2) + b(a - 2) = (a-2)(3a+b)
3. t^3 - t^2 + t - 1 = t^2(t - 1) + (t - 1) = (t-1)(t^2+1)
4. 10 + 2t - 5s - st = 10 - 5s + 2t - st = 5(2 - s) + t(2-s) = (5+t)(2-s)
4 0
3 years ago
Solve for side length, a. Round to one decimal place."
barxatty [35]
Answer b

Reason:looked it up ;)
3 0
3 years ago
Marjorie needs to calculate how much water a cylindrical tank will hold. The tank is 9 feet high and has a diameter of 5 feet. H
aniked [119]

Answer:

The volume of the cylindrical tank is 176.625 cubic feet.

Step-by-step explanation:

Given : The tank is 9 feet high and has a diameter of 5 feet.

To find : Marjorie needs to calculate how much water a cylindrical tank will hold ?

Solution :

The volume of a cylinder is V=\pi r^2 h

The diameter is d=5 feet

The radius is r=\frac{d}{2}

r=\frac{5}{2}=2.5 feet.

The height is h=9 feet.

Substitute the value in the formula,

V=3.14\times (2.5)^2\times 9

V=3.14\times 6.25\times 9

V=176.625

The volume of the cylindrical tank is 176.625 cubic feet.

8 0
3 years ago
Read 2 more answers
Which table of values is correct for the equation y = 5(2)x
Tems11 [23]

Answer:

Option D is correct.

x             y

0             5

1              10

2              20

Step-by-step explanation:

Given the equation:  y = 5(2)^x           .....[1]

Here, x is the input variable and y is the output variable.

For x =0

Substitute in equation [1]; we have;

y = 5(2)^{0} = 5 \cdot 1= 5

For x = 1

Substitute in equation [1]; we have;

y = 5(2)^{1} = 5 \cdot 2= 10

For x =2

Substitute in equation [1]; we have;

y = 5(2)^{2} = 5 \cdot 4= 20

Therefore, the table values which is correct for the equation y = 5(2)^x  is;

x             y

0             5

1              10

2              20

5 0
3 years ago
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