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OleMash [197]
3 years ago
13

Q 1 What is rusting?

Chemistry
2 answers:
blondinia [14]3 years ago
8 0

Answer:

Rust is a chemical reaction (oxidation) of iron that occurs over a period of time as the bare metal surface comes in contact with oxygen present in the air or water. Rust "eats" away the metal, rendering it weak and fragile. ... Avoid contact with water or moisture.

professor190 [17]3 years ago
5 0
Rusting is an oxidation reaction. The iron reacts with water and oxygen to form hydrated iron(lll) oxide, which we see as rust
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The electron configuration for an atom is 1s 2s 2p2. How many electrons does the atom have?
taurus [48]

Answer:

Four  

Step-by-step explanation:

The <em>superscripts</em> in an electron configuration tell us how many electrons are in a subshell.

If the electron configuration is 1s¹ 2s¹2p², the total number of electrons is

1 + 1 + 2 = 4

The atom contains four electrons.

<em>Note</em>: this atom is in an <em>excited state</em>, because the 1s and 2s subshells can each hold one more electron.

7 0
3 years ago
Why can metals be extracted using carbon
8090 [49]
If a metal is less reactive than carbon, it can be extracted from its oxide by heating with carbon. The carbon displaces the metal from the compound, and removes the oxygen from the oxide. This leaves the metal.
5 0
2 years ago
The reaction 2NO(g)+Cl2(g)→2NOCl(g) is carried out in a closed vessel. If the partial pressure of NO is decreasing at the rate o
Luba_88 [7]

Answer : The rate of change of the total pressure of the vessel is, 10.5 torr/min.

Explanation : Given,

\frac{d[NO]}{dt} =21 torr/min

The balanced chemical reaction is,

2NO(g)+Cl_2(g)\rightarrow 2NOCl(g)

The rate of disappearance of NO = -\frac{1}{2}\frac{d[NO]}{dt}

The rate of disappearance of Cl_2 = -\frac{d[Cl_2]}{dt}

The rate of formation of NOCl = \frac{1}{2}\frac{d[NOCl]}{dt}

As we know that,

\frac{d[NO]}{dt} =21 torr/min

So,

-\frac{d[Cl_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}

\frac{d[Cl_2]}{dt}=\frac{1}{2}\times 21torr/min=10.5torr/min

And,

\frac{1}{2}\frac{d[NOCl]}{dt}=\frac{1}{2}\frac{d[NO]}

\frac{d[NOCl]}{dt}=\frac{d[NO]}=21torr/min

Now we have to calculate the rate change.

Rate change = Reactant rate - Product rate

Rate change = (21 + 10.5) - 21 = 10.5 torr/min

Therefore, the rate of change of the total pressure of the vessel is, 10.5 torr/min.

8 0
3 years ago
Biodiversity is the ___________
riadik2000 [5.3K]

Answer:

answer is 1.A measurment of the...

4 0
3 years ago
Express the frequency in inverse seconds. n=4--&gt;n=3. Can you please tell me what formulas to use, because I have like 6 more
bulgar [2K]

Answer:

  • 1.60×10¹⁴ s⁻¹

Explanation:

When an electron jumps from one energy level to a lower energy level some energy is released in the form of a photon.

The difference in energy between the two levels is the energy of the photon and that energy is related to the frequency of the photon by the Einstein - Planck equation:

  • E = hν

Where,

  • E = energy of the photon,
  • h = 6.626×10⁻³⁴ J.s, Planck constant, and
  • ν = frequency of the photon.

So, to find the frequency you must first find the energy.

The transition energy can be calculated using the formula:

  • Eₙ = - E₀ ( 1/ n²)

Where E₀ = 13.6 eV ( 1 eV = 1.602×10⁻¹⁹ Joules) and n = 1,2,3,...

So, the transition energy between n = 4 and n = 3 will be:

  • ΔE = - E₀ [ 1/4² - 1/3²] = - 13.6 eV [1/16 - 1/9] = 0.6611. . .eV

  • ΔE = 1.602×10⁻¹⁹ Joules/eV  × 0.6611... eV = 1.0591 ×10⁻¹⁹ Joules

Now you can use the Einstein - Planck equation:

  • E = hν
  • ν = E / h
  • ν = 1.0591 ×10⁻¹⁹ J / 6.626×10⁻³⁴ J.s  = 1.60×10¹⁴ s⁻¹ (rounded to 3 significant figures).
3 0
3 years ago
Read 2 more answers
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