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Pani-rosa [81]
3 years ago
6

The Earth orbits the Sun at a speed of 30 km/s. At that speed it completes one path around the Sun every year. Of course, as tha

t happens we are heading toward a different place in space constantly, always accelerating toward the Sun to stay on the circular path. Suppose at a paritcular instant we are headed in the direction of a distant star and we measure the speed of the light from that star as it arrives on Earth. In the vacuum of space we would measurea. 299,792,458 m/sb. 299,792,428 m/sc. 299,792,488 m/sd. 0 m/s
Physics
1 answer:
romanna [79]3 years ago
3 0

Answer:

a. 299,792,458 m/s

Explanation:

Since the speed of light in a vacuum is invariant and has the value of 299,792,458 m/s, we would measure this value of 299,792,458 m/s for the speed of light from the star as it arrives on Earth.

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What is the amplitude of an AC voltage waveform, in units of Volts, if the RMS value is 369 V?
Blizzard [7]

Answer:

521.8 V

Explanation:

The RMS value of the voltage of an AC signal is given by

V_{rms}=\frac{V_0}{\sqrt{2}}

where

V_0 is the peak voltage, which corresponds to the amplitude of the AC waveform

In this problem, we know the RMS voltage

V_{rms}=369 V

Therefore, we can re-arrange the previous equation to find the peak voltage (the amplitude of the waveform):

V_0 = \sqrt{2}V_{rms}=\sqrt{2}(369 V)=521.8 V

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Answer:

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Ann [662]

Answer:

b

Explanation:

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