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3 years ago

How does the size of a planet affected the amount and type of gas in its atmosphere

1 answer:

3 0

There are lots of variables that directly and indirectly contribute to the presence of gas on a surface
if the size of a planet is relatively small it will in turn be that of a smaller area which results in the less area to be covered for gas which basically means higher presence
I can go in depth more but I don't think that would be necessary all you need to know is this ...based on the size and gas will in turn be parallel to it's conformity

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Two wooden boxes of equal mass but different density are held beneath the surface of a large container of water. Box A has a sma

sweet [91]

Answer:

As a box A has a smaller average density than box B, then it will have a greater acceleraton towards the surface upon releasing. So the option E) Box A is a correct option.

Explanation:

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4 years ago

Water in a tank which is positioned 5 feet above the ground is _____ potential energy? (answers would be like thermal, electric,

LUCKY_DIMON [66]

Answer:

Mechanical

Explanation:

The tank is at rest. And energy of any substance at rest is known as potential energy.

Now, in forms of energy, potential energy is a type of mechanical energy.

Thus, the correct option is mechanical Energy.

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3 years ago

A ball is thrown straight up into the air with an initial speed of 8.0 m/s. How long does it take for the rocket to reach its hi

andrezito [222]

What is the highest point??

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3 years ago

Read 2 more answers

A wire has a cross sectional area of 4.00 mm2 and is stretched by 0.100 mm by a certain force. How far will a wire of the same m

Nina [5.8K]

Answer: $0.05\ mm$

Explanation:

Given

Cross-sectional area of wire $A_1=4\ mm^2$

Extension of wire $\delta l=0.1\ mm$

Extension in a wire is given by

$\Rightarrow \delta l=\dfrac{FL}{AE}$

where, $E=\text{Youngs modulus}$

$\Rightarrow \delta_1=\dfrac{FL}{A_1E}\quad \ldots(i)$

for same force, length and material

$\Rightarrow \delta_2=\dfrac{FL}{A_2E}\quad \ldots(ii)$

Divide (i) and (ii)

$\Rightarrow \dfrac{0.1}{\delta_2}=\dfrac{A_2}{A_1}\\\\\Rightarrow \delta_2=0.1\times \dfrac{4}{8}\\\\\Rightarrow \delta_2=0.05\ mm$

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3 years ago

A tow truck drags a stalled car along a road. The chain makes an angle of 30° with the road and the tension in the chain is 1400

AURORKA [14]

Answer:

The work is done by the truck pulling the car 1 km is 1,212,436 J

Explanation:

Work is defined as the force that is applied on a body to move it from one point to another. When a force is applied, an energy transfer occurs. Then it can be said that work is energy in motion.

So work is one of the forms of energy transmission between bodies. To perform a job, you must exert a force on a body and it moves.

In the International System of Units, work is measured in Joule. A Joule is the work that a constant force of 1 Newton does on a body that moves 1 meter in the same direction and direction as the force. Then, Joule is equivalent to Newton per meter.

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves:

Work= Force*Distante* cos (θ)

In this case:

Force= 1,400 N= 1,400 $kg*\frac{m}{s^{2} }$

Distance= 1 km= 1,000 m

θ= Angle that exists between the direction of the force and the direction= 30°

Replacing:

Work= 1,400 N* 1,000 m* cos (30°)

Work= 1,212,435. 565 Joule≅ 1,212,436 J

<u><em> The work is done by the truck pulling the car 1 km is 1,212,436 J</em></u>

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3 years ago