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attashe74 [19]
3 years ago
14

If one replaces the conducting cube with one that has positive charge carriers, in what direction does the induced electric fiel

d point
Physics
1 answer:
Grace [21]3 years ago
3 0

Answer:

There will be no change in the direction of the electric field .

Explanation:

The direction will remain the same because the sign of the charges has no effect on it.

When one replaces the conducting cube with one that has positive charge carriers there will be no change in the direction of the field as there is no defined relationship between the direction of the electric field and sign of the charge.

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. Suppose that the displacement of an object is related to time according to the expression: x(t) = B t3 . Using dimensional ana
-Dominant- [34]

Answer:

The dimensionality of B is <em>length</em> per cubic <em>time</em>.

Explanation:

Units for displacement and time are <em>length</em> [L] and <em>time</em> [T], respectively. Then, formula can be tested for dimensional analysis as follows:

[L] = B\cdot [T]^{3}

Now, let is clear B to determine its units:

B = \frac{[L]}{[T]^{3}}

The dimensionality of B is <em>length</em> per cubic <em>time</em>.

6 0
3 years ago
A ticker-tape is moved through a ticker-timer for 5 seconds . if the timer is operating at 25 Hz. i.How many dots would have bee
svetlana [45]

Answer:

Explanation:

25 cycles/s (5 s) = 125 dots

Tape does Repetitious motion.

It might possibly be harmonic motion, but we do not have enough information to say for certain.

8 0
2 years ago
Carbohydrates are made of hydrogen, oxygen, and which of the following? A. nitrogen B. carbon C. helium D.argon
k0ka [10]
The answer would be carbon
4 0
3 years ago
A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an
maksim [4K]

Answer:

The  value is   \alpha =  0.002 Np/m

Explanation:

From the question we are told that

  The first amplitude of the wave is  E_{max}1 =  98.02 \  V/m

  The first  depth  is  D_1 =  10 \  m

   The second amplitude is  E_{max}2 =  81.87 \  (V/m)

   The second depth is D_2 = 100 \ m

Generally from the spatial wave equation we have

   v(x) =  Ae^{-\alpha d}cos(\beta x  + \phi_o)

=>       \frac{v(x)}{v(x)} =\frac{  Ae^{-\alpha d}cos(\beta x  + \phi_o)}{ Ae^{-\alpha d}cos(\beta x  + \phi_o)}

So considering the ratio of the equation for the  two depth

\frac{A}{A_S}  =  \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}

=>   \frac{98.02}{81.87}  =  \frac{e^{-10 \alpha }}{e^{-100 \alpha }}

=>   \alpha  =  \frac{0.18}{90}

=>    \alpha =  0.002 Np/m

       

4 0
3 years ago
How is my Engineering Project?
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What do you mean you need to be more specific
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