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attashe74 [19]
3 years ago
14

If one replaces the conducting cube with one that has positive charge carriers, in what direction does the induced electric fiel

d point
Physics
1 answer:
Grace [21]3 years ago
3 0

Answer:

There will be no change in the direction of the electric field .

Explanation:

The direction will remain the same because the sign of the charges has no effect on it.

When one replaces the conducting cube with one that has positive charge carriers there will be no change in the direction of the field as there is no defined relationship between the direction of the electric field and sign of the charge.

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Allisa [31]

Given data:

  • It is a graphical display where the data is grouped in to ranges
  • A diagram consists rectangles, whose area is proportional to frequency of a variable and whose width is equal to the class interval.
  • It is an accurate representation of the distribution of numerical data.

<em>From Figure:</em>  

        Each box in the graph (small rectangle box) is assumed to be one download. So, in the graph the time between 8 p.m to 9 p.m, the number of downloads are 8.75 approximately (because the last box is incomplete, therefore 8 complete boxes and 9th is more than half).

<em>So, We conclude that the total number of downloads are approximately 9 in the time span of 8 p.m. to 9 p.m.</em>

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2 years ago
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solong [7]

Answer:

Explanation:

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2 years ago
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Alexeev081 [22]

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2 years ago
A plane traveling horizontally at 120 ​m/s over flat ground at an elevation of 3610 m must drop an emergency packet on a target
allsm [11]

Answer:

Explanation:

Horizontal displacement

x = 120 t

Vertical position

y = 3610 - 4.9 t²

y = 0 for the ground

0 = 3610 - 4.9 t²

t = 27.14 s

This is the time it will take to reach the ground .

During this period , horizontal displacement

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So packet should be released 3256.8 m before the target.

3 0
3 years ago
Read 2 more answers
A bus starts from rest.if the acceleration is 2m/s square, find
MrMuchimi

Answer:

The velocity after 2 seconds can be found through:

V = u +a*t

Where V is final velocity, u is initial velocity, a is acceleration and t is time.

V = 0 + 2* 2= 4 meters/second

The distance (s) can be found through:

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4^2= 0^2 + 2 *2*s

16= 0 + 4s

s= 4 meters

Distance (s) can also be found through:

s= ut + 1/2 at^2

s= 0+ 1/2 *2*2^2= 1 *2*2

s= 4 meters

Explanation:

3 0
1 year ago
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