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White raven [17]
2 years ago
8

Answering the easy questions first is

Chemistry
1 answer:
Setler79 [48]2 years ago
8 0

Answer:

ddfdsfd

Explanation:

sdgh   hjrtj

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The figure shows the hybrid orbitals of methane. mc022-1.jpg Which molecule has the same shape and hybridization as methane? SO3
Orlov [11]
METHANE - sp³ - shape: tetrahedral
....................
SO₃ - sp² - shape: trigonal
C₂H₂ - sp - shape: linear
CH₂O - sp² - shape: trigonal
CF₂Cl₂ - sp³ - shape: tetrahedral
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Which molecule has the same shape and hybridization as methane?
CF₂Cl₂ (difluorodichloromethane)
4 0
3 years ago
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Plz help, if you don't know the answer please don't answer it
Semenov [28]

Answer:

1. 71 and 29

2. 97 and 3

3. 2.1 and 1.2

Explanation:

6 0
3 years ago
Water vapor particles are most likely to phase change into liquid particles if the vapor particles come into contact with
dalvyx [7]
Water vapour particles are most likely to phase change into liquid particles if the vapour particle come into contact with A COOLER SURFACE.
For a liquid to change to gas, it has to absorb enough energy to break the chemical bond that is holding the liquid particles together. When a liquid change to gas it is called vaporization. When a vapour, for instance water vapour comes in contact with cooler surfaces they lose energy and get converted back to the liquid state; this process is called condensation.
8 0
3 years ago
How are t cells and b cells same
tigry1 [53]
T cells and B cells are similar because they both deal with fighting of viruses.
5 0
3 years ago
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Please help with #2 and #3
Vaselesa [24]

Answer:

2. V_2=17L

3. V=82.9L

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

\frac{V_2}{T_2}=\frac{V_1}{T_1}

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

V_2=\frac{V_1T_2}{T_1}

Therefore, we plug in the given data to obtain:

V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

V=\frac{nRT}{P}

Therefore, we plug in the data to obtain:

V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L

Best regards!

6 0
3 years ago
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