Answering the easy questions first is

There are 43.2 g of carbon to 14.4 g of hydrogen in a sample of methane (CH4). What percent of 37.8 g of methane is carbon?

EastWind [94]

Using the law of constant proportions which says that within the same compound, elements exist in fixed ratios.

Therefore; we can use the ratio of total mass to the mass of carbon, to determine the amount of carbon in another sample.

Mass C / Mass CH4 = Mass C / Mass CH4

43.2 g / 57.6 g = Mass C / 37.8 g

Mass C = 37.8 g × 43.2 g / 57.6 g

= 28.35 g

Hence; the percentage of carbon will be;

=(28.35/ 37.8 )× 100%

= 75 %

Thus; 75% of 37.8 g of methane is carbon

8 0

3 years ago

Two elements that have properties similar to those of the element potassium(K). To those of krypton(Kr)

balu736 [363]

Answer:

Calcium (Ca) and Scandinavium (Sc)

Explanation:

They are all on the same period.

8 0

3 years ago

Which processes produce solute ions in a solution?

bonufazy [111]

The answer for this question is B) Ionization and Dissociation because Dissociation happens, charged particles form (ions), and since the ions didn't exist before the substance was dissolved, this process is called IONIZATION. It is the process that involves the formation of ions, a conversion of a substance into ions.

8 0

3 years ago

Read 2 more answers

Summarize the weather conditions related to a cold front. Remember to include all data collected on cold fronts in this activity

svp [43]

Answer: Many fronts cause weather events such as rain, thunderstorms, gusty winds and A weather front is a transition zone between two different air masses at the Lifted warm air ahead of the front produces cumulus or cumulonimbus clouds

Explanation:

Hope this was helpful

5 0

3 years ago

Enter your answer in the provided box. When mixed, solutions of barium chloride, BaCl2, and potassium chromate, K2CrO4, form a y

ira [324]

Answer:

35.42g

Explanation:

Step 1:

The balanced equation for the reaction

BaCl2(aq) + K2CrO4(aq) → BaCrO4(s) + 2KCl(aq)

Step 2:

Determination of the limiting reactant.

It is important to determine which of the reactant is limiting the reaction as the limiting reactant is used to determine the maximum yield of the reaction. The limiting reactant can be determined as follow:

From the balanced equation above,

1 mole of BaCl2 reacted with 1 mole of K2CrO4.

Therefore, 0.7 mole of BaCl2 will also react with 0.7 mol of K2CrO4.

From the above illustration, we can see that it requires a higher amount of K2CrO4 to react with 0.7 mol of BaCl2. This simply means that K2CrO4 is the limiting reactant.

Step 3:

Determination of the number of mole of BaCrO4 produced from the reaction.

The limiting reactant is used in this case.

From the balanced equation above,

1 mole of K2CrO4 produced 1 mole of BaCrO4.

Therefore, 0.14 mole of K2CrO4 will also produce 0.14 mole of BaCrO4.

Step 4:

Converting 0.14 mole of BaCrO4 to grams.

This is illustrated below:

Molar Mass of BaCrO4 = 137 + 52 + (16x4) = 137 + 52 + 64 = 253g/mol

Number of mole BaCrO4 = 0.14 mole

Mass of BaCrO4 =?

Mass = number of mole x molar Mass

Mass of BaCrO4 = 0.14 x 253

Mass of BaCrO4 = 35.42g

Therefore, 35.42g of BaCrO4 is produced from the reaction.

4 0

3 years ago