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sashaice [31]
3 years ago
7

What’s the answer for this question which i have posted can I know the answers as possible

Chemistry
1 answer:
Hitman42 [59]3 years ago
3 0

The change in internal energy = 2.701 x 10² kJ

<h3>Further explanation</h3>

Given

Heat absorbed by system = 1.69 x 10² kJ

Work done on system = 1.011 x 10² kJ

Required

The change in Internal energy

Solution

We can use the first law of Thermodynamics :

\tt \Delta U=Q+W

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

Heat absorbed/receive heat from surrounding = Q+

Work done on the system = W+

and input the given values

\tt \Delta U= 1.69\times 10^2+1.011\times 10^2\\\\\Delta U=\boxed{\bold{2.701\times 10^2~kJ}}

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The visual or mathematical representation of an object system or concept is known as a model. Hope this helps and mark as brainliest!
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4 years ago
A 33.153 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap
elena-14-01-66 [18.8K]

Answer:

The empirical formula of the compound = C_4H_8S_1O_1

Explanation:

Mass of carbon dioxide gas = 59.060 mg = 0.059060 g

1 mg = 0.001 g

Moles of carbon dioxide = \frac{0.059060 g}{44 g/mol}=0.0013 mol

Moles of carbon in 0.0013 moles of carbon dioxide gas = 1 × 0.0013 mol = 0.0013 mol

Mass of 0.0013 moles of carbon = 12 g/mol\times 0.0013 mol=0.0156 g

Mass of water = 24.176 mg = 0.024176

Moles of water = \frac{0.024176 g}{18 g/mol}=0.0013 mol

Moles of hydrogen in 0.0013 moles of water = 2 × 0.0013 mol = 0.0026 mol

Mass of 0.0013 moles of hydrogen= 1 g/mol\times 0.0013 mol=0.0013 g

Mass of sulfur dioxide = 20.326 mg = 0.020326 g

Moles of sulfur dioxide = \frac{0.020326 g}{64 g/mol}=0.00032 mol

Moles of sulfur in 0.00032 moles of sulfur dioxide = 1 × 0.00032 mol = 0.00032 mol

Mass of 0.00032 moles of sulfur = 32 g/mol\times 0.00032 mol=0.01024 g

Mass of oxygen in the sample = x

Mass of sample = 33.153 mg = 0.033153 g

0.033153 g = 0.0156  g + 0.0013 g + 0.01024 g + x

x = 0.006013 g

Moles of oxygen = \frac{0.006013 g}{16 g/mol}=0.00038 mol

For empirical formula divide the lowest number of moles of elemnt from all the moles of the all the elements:

Carbon : \frac{0.0013 mol}{0.00032 mol}=4

Hydrogen: \frac{0.0026 mol}{0.00032 mol}=8

Sulfur : \frac{0.00032 mol}{0.00032 mol}=1

Oxygen : \frac{0.00038 mol}{0.00032 mol}=1

The empirical formula of the compound = C_4H_8S_1O_1

8 0
4 years ago
When metal atoms combine chemically with atoms of other elements, what do they usually do?
Fiesta28 [93]

Answer:

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The answer you'll be expected to give depends on the subject of the chapter you're studying. If you're studying covalent bonds, then the answer will probably be "form covalent bonds". If you're studying ionic bonds, then the answer will be "lose electrons".

Explanation:

This may not be the answer... I'm sorry if it's not

8 0
3 years ago
How many molecules are in 25g of Na2SO4?
bearhunter [10]
Hey there!

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Number of moles:

n = m / mm

n = 25 / 142.04

n = 0.176 moles of Na2SO4

Therefore, use the Avogadro constant

1 mole Na2SO4 ------------------- 6.02x10²³ molecules
0.176 moles Na2SO4 ------------   molecules ??


0.176  x  ( 6.02x10²³ ) / 1 

=> 1.059x10²³ molecules of Na2SO4

hope this helps!


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3 years ago
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Answer:

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Explanation:

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