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sashaice [31]
3 years ago
7

What’s the answer for this question which i have posted can I know the answers as possible

Chemistry
1 answer:
Hitman42 [59]3 years ago
3 0

The change in internal energy = 2.701 x 10² kJ

<h3>Further explanation</h3>

Given

Heat absorbed by system = 1.69 x 10² kJ

Work done on system = 1.011 x 10² kJ

Required

The change in Internal energy

Solution

We can use the first law of Thermodynamics :

\tt \Delta U=Q+W

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

Heat absorbed/receive heat from surrounding = Q+

Work done on the system = W+

and input the given values

\tt \Delta U= 1.69\times 10^2+1.011\times 10^2\\\\\Delta U=\boxed{\bold{2.701\times 10^2~kJ}}

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3 years ago
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3CaCl2+Al2O3 -------->3CaO +2AlCl3
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3 years ago
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