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ANEK [815]
4 years ago
11

When temperatures are below freezing, the temperature at which air becomes saturated leading to the formation of frost is the

Chemistry
1 answer:
12345 [234]4 years ago
4 0

Answer:

The answer is Frost Point.

Explanation:

The temperature to which the air must be cooled, with constant pressure, to reach saturation (in relation to liquid water), is called the dew point. The dew point gives a measure of the water vapor content in the air. The higher, the greater the concentration of water vapor in the air. However, when cooling produces saturation at a temperature of 0 ° C or less, the temperature is called a frost point. The water vapor is deposited as frost on a surface whose temperature is below the dew point.

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0.2344 mol CH3OH/0.0500=
BigorU [14]

Answer:

150.016 grams

Explanation:

molar mass of cH3OH=12+4+16 =32 u

mass = nu. of moles × molar mass

mass= 0.2344 × 32 =7.5008 gm÷ 0.0500 = 150.016 gm

8 0
4 years ago
__NH3 + __O2 → __NO + __H2O<br> How many moles of water are produced from<br> 2.48 g of oxygen?
Dennis_Churaev [7]
I hope this helps in some way. I forgot to mention that the question states they want to find THE NUMBER OF MOLES for H2O. Yherefore, you would want mol of H2O on top.

4 0
3 years ago
Which of the following is the correctly balanced equation for the reaction of a Ca(OH)2 and HNO3
lakkis [162]
Your answer is
Ca(OH)₂ + 2HNO₃ → Ca(NO₃)₂ + 2H₂O I hope it is at least :P
4 0
3 years ago
For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of
Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe  = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O;  Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

 


7 0
3 years ago
Read 2 more answers
Low tide____.
Fantom [35]

Answer:

i think the answer is A

Explanation:

because in some areas, a regular pattern occurs of one high tide and one low tide each day,

8 0
3 years ago
Read 2 more answers
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