Answer:
number protons and force are Q = 1,472 10⁻¹⁷ C F = 3,656 10⁻⁸ N
Explanation:
Atoms are neutral whereby the number of electrons in the atom is compensated by an equal number of positively charged protons in the nucleus, so there are 92 protons, the total charge can be found by a rule of proportions
Q = # proton * 1.6 10⁻¹⁹C
Q = 92 * 1.6 10⁻¹⁹
Q = 1,472 10⁻¹⁷ C
To calculate the force of an electron we use Coulomb's law
F = k q1 Q / r²
F = k e Q / r²
The Coulomb constante is 8.99 10⁹ N m² /C²
F = 8.99 10⁹ 1.6 10⁻¹⁹ 1,472 10⁻¹⁷ / (7.61 10⁻¹⁰)²
F = 3,656 10⁻⁸ N
This force is attractive.
Answer:
1. The answer is that there will be more force with more speed.
2. less speed means less force.
3. And last, but certainly not the least, the less the mass has, the less the force will be, unless the object is moving at a high speed.
Explanation:
Answer:
Explanation:
See the file attached .
b ) Range of projectile
= u²sin2θ / g
= 42² sin32 x 2 / g
= 42² sin64 / 9.8
= 161.8 m
c )
Max height = u² sin²32 / 2 g
= 42² sin²32 / 2x 9.8
= 25.27 m .
Answer:
Force, ![F=2.27\times 10^4\ N](https://tex.z-dn.net/?f=F%3D2.27%5Ctimes%2010%5E4%5C%20N)
Explanation:
Given that,
Mass of the bullet, m = 4.79 g = 0.00479 kg
Initial speed of the bullet, u = 642.3 m/s
Distance, d = 4.35 cm = 0.0435 m
To find,
The magnitude of force required to stop the bullet.
Solution,
The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :
![F.d=\dfrac{1}{2}m(v^2-u^2)](https://tex.z-dn.net/?f=F.d%3D%5Cdfrac%7B1%7D%7B2%7Dm%28v%5E2-u%5E2%29)
Finally, it stops, v = 0
![F.d=-\dfrac{1}{2}m(u^2)](https://tex.z-dn.net/?f=F.d%3D-%5Cdfrac%7B1%7D%7B2%7Dm%28u%5E2%29)
![F=\dfrac{-mu^2}{2d}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B-mu%5E2%7D%7B2d%7D)
![F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B-0.00479%5Ctimes%20%28642.3%29%5E2%7D%7B2%5Ctimes%200.0435%7D)
F = -22713.92 N
![F=2.27\times 10^4\ N](https://tex.z-dn.net/?f=F%3D2.27%5Ctimes%2010%5E4%5C%20N)
So, the magnitude of the force that stops the bullet is ![2.27\times 10^4\ N](https://tex.z-dn.net/?f=2.27%5Ctimes%2010%5E4%5C%20N)
In a vacuum, all objects fall at the same rate. Meaning that the 100 kg ball will fall at the same speed as the 10 kg ball. Assuming that both objects share the same starting acceleration, they will keep that acceleration until the fall is stopped.
In other words, your answer is the first one, Both objects will accelerate at 9.8 m/s