Answer:The tangential acceleration is 0 m/s².
Explanation:Given:
Radius of the wheel = 0.5 m
The point of observation for calculating tangential acceleration = 0.2 m from center.
Tangential speed at the point of observation = 2 m/s
The angular speed of the wheel is a constant.
In order to determine the tangential acceleration, we make use of the following formula:
Tangential acceleration at a point = Angular acceleration × Distance of the point from center
Or, a_t=\alpha \times r
Now, angular acceleration is defined as the rate of change of angular speed.
Here, the angular speed of the wheel is a constant. So, the change of angular speed is 0. Therefore, the angular acceleration is also 0 rad/s².
Now, from the above formula, as angular acceleration is 0, the magnitude of tangential acceleration at a point that is 0.2 m from the center of the wheel is also 0 m/s².
Hope it helped
Answer:
Both A and B
Explanation:
Slow cranking and excessive current draw are common problems that arise whenever a mechanical fault is within a system and also when motor starter is ineffective or binding. Therefore, both technicians are correct
Answer:
17.284 rad/s^2
Explanation:
F = 337 N
R = 0.398 m
M = 98 kg
let the angular acceleration is α
torque = I x α = F x R
Where I is the moment of inertia
I = 1/2 MR^2 = 0.5 x 98 x 0.398 x 0.398 = 7.76 kg m^2
So,
7.76 x α = 337 x 0.398
α = 17.284 rad/s^2
I honestly think it's 18,000 N
Hope I helped!
<span>So if you started on the bench press with 8 reps of 225 pounds, but can now do 10 reps, and you've been able to achieve 10 reps for two workouts in a row, increase the weight.
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Theres a little exclamation......