Answer:
V=3 m/s
t=12 seconds
S=?
S=V×t
S=3×12
S=36meters
So distance you travel is 36meters.
Answer:
yes
Explanation:
Let's solve your equation step-by-step.
4x+3=−5
Step 1: Subtract 3 from both sides.
4x+3−3=−5−3
4x=−8
Step 2: Divide both sides by 4.
4x / 4 = −8 / 4
x=−2
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Answer: Q=5.46 L/s
COP=2.58
Explanation:
Given that
Cp = 4.18 kJ/(kg.C
density = 1 kg/L
Heat rejected Qr= 570 kJ/min
Power in put W= 2.65 KW
From first law of thermodynamics
U = W+ q
q = Heat absorbed
U = internal energy
W = workdone
U = 570 kJ/min = 9.5 KW
9.5 = 2.65 + q
q = 6.85 KW
COP = q/W
COP = 6.58 / 2.65
COP=2.58
Lets take volume flow rate is Q
So mass flow rate of water m = ρ Q
q = m Cp ΔT
6.85 = 1 x Q x 4.18 ( 23-5)
Q=0.091 L/min
Q=5.46 L/s
Answer:
This question will be answered based on general photosynthetic understanding. The answer is:
The production of oxygen would increase
Explanation:
The characteristics of most plant forms is their ability to photosynthesize i.e. use solar energy (from sunlight) to make food (chemical energy). The product of this photosynthetic process is OXYGEN gas, which is released as a waste product via the stomata on their leaves. Note that, photosynthesis cannot occur without LIGHT as it provides the energy needed for the process.
Hence, in the duckweed plant like every other photosynthetic plant, the increase in the intensity and duration of exposure to light means the rate at which photosynthesis occurs will be increased. An increased photosynthetic rate means the synthesis of the products will also be increased i.e. glucose and OXYGEN.
Answer: 0.4 m
Explanation:
Given
Speed of ambulance, vs = 61.9 m/s
Speed of car = 28.5 m/s
Frequency of ambulance siren, f = 694 Hz
Velocity of sound in air, v = 343 m/s
With speed of ambulance being (61.9 m/s) -> We solve using
fd = f(v + vr) / (v - vs), where vr = 0
fd = 694 * (343 + 0) / (343 - 61.9)
fd = 694 * (343 / 281.1)
fd = 694 * 1.22
fd = 847 Hz
Recall,
λ = v/f
λ = 343/847
λ = 0.4 m
Therefore, the wavelength of the sound of the ambulance’s siren if you are standing at the position of the car is 0.4 m
