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Ad libitum [116K]
2 years ago
13

Given that the rms of a helium atom at a certain temperature is 1350 m s-1, determine the rms speed of an oxygen molecule at thi

s temperature. The molar mass of O2 is 32 g mol-1 and for He is 4 g mol-1.
Physics
1 answer:
monitta2 years ago
5 0

Answer:

Isko moreno vs Alfredy I will gonna go to sleep soon though you were able and willing and ready to play some games ☺️☺️

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Which of the following has the least amount of kinetic energy?
alexandr1967 [171]

Answer:

a 10 kg elephant moving at 1 m/s

Explanation:

because kinetic energy depend on how fast an object moves and also depend on the gravitational force which include the weight.

8 0
3 years ago
An engine has an energy input of 125 J, and 35 J of that energy is transformed into useful energy. What is the efficiency of the
Korolek [52]
Efficiency = (useful output) / (input)

Efficiency = (35 J) / (125 J) = 0.28  =  28%
8 0
3 years ago
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A 1.8-kg object is attached to a spring and placed on frictionless, horizontal surface. A force of 40 N stretches a spring 20 cm
Sergio [31]

Answer:

a) k = 200 N/m

b) E = 4 J

c) Δx = 6.3 cm

Explanation:

a)

  • In order to find force constant of the spring, k, we can use the the Hooke's Law, which reads as follows:

       F = - k * \Delta x (1)

  • where F = 40 N and Δx =- 0.2 m (since the force opposes to the displacement from the equilibrium position, we say that it's a restoring force).
  • Solving for k:

       k =- \frac{F}{\Delta x} =-\frac{40 N}{-0.2m} = 200 N/m (2)

b)

  • Assuming no friction present, total mechanical energy mus keep constant.
  • When the spring is stretched, all the energy is elastic potential, and can be expressed as follows:

        U = \frac{1}{2}* k* (\Delta x)^{2} (3)

  • Replacing k and Δx by their values, we get:

       U = \frac{1}{2}* k* (\Delta x)^{2} = \frac{1}{2}* 200 N/m* (0.2m)^{2} = 4 J (4)

c)

  • When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.
  • We know that due to the conservation of energy, this sum will be equal to the total energy that we found in b).
  • So, we can write the following expression:

        \frac{1}{2}* k* \Delta x_{1} ^{2} + \frac{1}{2} * m* v^{2}  = \frac{1}{2}*k*\Delta x^{2}   (5)

  • Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:

        \frac{1}{2}* 200N/m* \Delta x_{1} ^{2} + \frac{1}{2} * 1.8kg* (-2.0m/s)^{2}  = 4J   (6)

⇒      \frac{1}{2}* 200N/m* \Delta x_{1} ^{2}   = 4J  - 3.6 J = 0.4 J (7)

⇒     \Delta x_{1}   = \sqrt{\frac{0.8J}{200N/m} } = 6.3 cm (8)

6 0
3 years ago
Which of the following pulley systems have/has a greater mechanical advantage than the one shown above?
astraxan [27]
Is there a picture or description?

8 0
3 years ago
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The bottom of cooking utensils are often kept black. Give reason​
stepan [7]

Answer:

absorb more heat and get heated quickly

Explanation:

7 0
3 years ago
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