Answer:
3.75 m/s
Explanation:
From the question given above, the following data were obtained:
Acceleration (a) = 1.5 m/s²
Initial velocity (u) = 0 m/s
Time (t) = 2.5 s
Final velocity (v) =?
a = (v – u) / t
1.5 = (v – 0) / 2.5
1.5 = v / 2.5
Cross multiply
v = 1.5 × 2.5
v = 3.75 m/s
Hence, the escape velocity of the squirrel is 3.75 m/s
Acceleration is given by change in velocity divided by change in time, so his acceleration should just be (10-5)/5 which is [tex] \frac{5}{2} \frac{m}{s^{2}} [tex]
The driveway is 40 meters plus 225/4. You can do the math.
Answer:
There are so many questions which one you don't know
Answer:
Explanation:
AVerage acceleration is the cjange in velocity with time
a = v-u/t
v is the final velocity = 48m/s
u is the initial velocity = 40m/s
t is the time = 6.5s
a = 48-40/6.5
a = 8/6.5
a = 1.23m/s²
Hence the magnitude of the car’s average acceleration during this period is 1.23m/s²
