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2 years ago

7

Tammy is a forensic investigator examining a body at a crime scene. She notes that the body is stiff but still flexible. What do

es she know about the time of death?

1 answer:

wlad13 [49]2 years ago

8 0

I may be wrong but does it mean it was revent? because i know shortly after someone dies your body becomes fully stiff so maybe it was recent and it's in the process off stiffening up

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The period of the earth around the sun is 1 year and its distance is 150 million km from the sun. An asteroid in a circular orbi

SOVA2 [1]

Answer:

5.024 years

Explanation:

T1 = 1 year

r1 = 150 million km

r2 = 440 million km

let the period of asteroid orbit is T2.

Use Kepler's third law

T² ∝ r³

So,

$\left ( \frac{T_{2}}{T_{1}} \right )^2=\left ( \frac{r_{2}}{r_{1}} \right )^3$

$\left ( \frac{T_{2}}{1} \right )^2=\left ( \frac{440}{150} \right )^3$

T2 = 5.024 years

Thus, the period of the asteroid's orbit is 5.024 years.

4 0

2 years ago

Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t

Readme [11.4K]

Answer: $3.66(10)^{33}kg$

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity $\omega$ of the planet P1 with a period $T=750years=2.36(10)^{10}s$ :

$\omega=\frac{2\pi}{T}=\frac{V_{1}}{R}$ (1)

Where:

$V_{1}=40.2km/s=40200m/s$ is the velocity of planet P1

$R$ is the radius of the orbit of planet P1

Finding $R$ :

$R=\frac{V_{1}}{2\pi}T$ (2)

$R=\frac{40200m/s}{2\pi}2.36(10)^{10}s$ (3)

$R=1.5132(10)^{14}m$ (4)

On the other hand, we know the gravitational force $F$ between the star S with mass $M$ and the planet P1 with mass $m$ is:

$F=G\frac{Mm}{R^{2}}$ (5)

Where $G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

In addition, the centripetal force $F_{c}$ exerted on the planet is:

$F_{c}=\frac{m{V_{1}}^{2}}{R^{2}}$ (6)

Assuming this system is in equilibrium:

$F=F_{c}$ (7)

Substituting (5) and (6) in (7):

$G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}}$ (8)

Finding $M$ :

$M=\frac{V^{2}R}{G}$ (9)

$M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}}$ (10)

Finally:

$M=3.66(10)^{33}kg$ (11) This is the mass of the star S

4 0

3 years ago

Which item contains a switch that opens when the current in a circuit is too high?

lana [24]

it is circuit breaker

3 0

2 years ago

Read 2 more answers

Suppose that the potential energy of a particle constrained

denpristay [2]

The graph of the potential energy pass through zero origin, cuts across positive x-axis and negative x-axis.

<h3>Slope of the graph</h3>

The slope of the graph when the potential energy of a particle constrained in on x-axis is determined as follows;

F = -dU/dx

-dU = Fdx

dU = -Fdx

U = -∫(kx + ax³)dx

U = kx²/2 - ax⁴/4

When, x = 0, U = 0

When U = 0;

$x = \pm \sqrt{\frac{2k}{a} }$

The graph of the potential energy pass through zero origin, cuts across positive x-axis and negative x-axis.

Complete question is below:

Suppose that the potential energy of a particle constrainedon x-axis and subjected to a force in the same direction, at a fuction of F(x) = -kx + ax³.

Find the functional form of the potential energy.

Learn more about potential energy here: brainly.com/question/1242059

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4 0

2 years ago

For the following equation answer the following:

sergij07 [2.7K]

Answer:

4Al + 3O2 + heat ------> 2Al2O3

Explanation:

It is endothermic reaction.

8 0

2 years ago