Given side AB in ΔABC has length x, what is the length of side AC?

. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person

bulgar [2K]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or greater

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 100, \sigma = 5$

What is the probability that a person selected at random will have an IQ of 110 or greater?

This is 1 subtracted by the pvalue of Z when X = 110. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{110 - 100}{5}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or greater

5 0

3 years ago

Please help. Thank you

Inessa [10]

Given:

$PQRS\sim TUVW$

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

$PQRS\sim TUVW$

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

$k=\dfrac{VW}{RS}$

$k=\dfrac{25}{35}$

$k=\dfrac{5}{7}$

Therefore, the scale factor from PQRS to TUVW is $k=\dfrac{5}{7}$ .

6 0

3 years ago

HELP NEEDED PLEASE!!!! This math question confuses me. I thought the line didn't pass through any other point but I cant figure

Vanyuwa [196]

Answer:

B

Step-by-step explanation:

So wiggly, remember that slope is change in y/change in x, or in simpler terms, y/x. Thinking of this, y/x must simplyfy to -3. Or, you can think of it as -3/1.

So know that we have rewrote this as a slope of -3/1, lets use it. Where do we start? Well, we must start at point A, which is at 2 x and 7 y.

Now, going to the RIGHT(+1x) and going DOWN(-3y) we will go from 2x and 7y to 3x and 4y.

Are we on a point yet? Nope, lets do this again.

Now going to RIGHT again(+1x) and going DOWN again(-3y) we will go from 13x and 4y to 4x and 1y.

Are we on a point yet? Still no, lets try this one more time.

Now going to RIGHT again(+1x) and going DOWN again(-3y) we will go from 4x and 1y to 5x and -2y.

Are we on a point? YUP. We cna see that point B is at 5x and -2y.

Hope you get it right ;)

4 0

2 years ago

Does the relation {(5,-2), (5,-8), (4,-6), (7,-1)} represent a function?

Sergio [31]

Answer:

no, it does not

Step-by-step explanation:

if it was a function, all the x values would've been different, but since 5 is repeated, it is not a function.

5 0

2 years ago

Write the Point-slope form of the equation of the line through giving point with the given slope.

Diano4ka-milaya [45]

3). y = -1/3x + 5

4). y = -1x +5

Slope intercept form: y = mx + b
m = slope
b = y intercept

4 0

3 years ago