Question

Rock A is thrown horizontally off of a cliff with a velocity of 20m/s. The rock lands 60m from the base of the cliff.

Answer 1

Answer:

B. 44.1

Explanation:

We can use the equation y=1/2gt^2 to find the distance in the vertical direction, where y= distance in the vertical direction, g=acceleration due to gravity, and t=time

we only know acceleration due to gravity(9.8m/s^2),

plug in known variables,

y=1/2*9.8*t^2

we still need to plug in the time variable.

In order to do that, we an use the s=d/t equation and re arrange that formula to get: t=d/s, where t=time, d=distance, and s=speed.

plug in known variables,

t=60/20

t=3

now that we know the time, we can plug that into our original equation

y=1/2*9.8*3^2

simplify,

y=4.9*3^2

y=4.9*9

y=44.1m

Thus, B is your answer