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2 years ago

If the mass of an ideal pendulum is doubled how will the oscillation period change?

1 answer:

5 0

Answer: Doubling the mass of the bob will half the period. b) If the length is doubled, the period will increase by a factor of √2 . The mass of the bob will not effect the period

Explanation:

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An object is thrown upward from the edge of a tall building as with a velocity of 10m/s. where will the object be 3s after it is

KonstantinChe [14]

20 m is the answer, hope that helps

6 0

3 years ago

If a food has 200 calories and 7 grams of protein, and each gram of protein is 4 calories, what percent of the serving comes fro

poizon [28]

Answer: 13%

Explanation: The reason this is 13 is because you can eat carlories and you can also be an amazing person 200 calories and 7 grams

4 0

2 years ago

A student releases a block of mass m at the top of a slide of height h1. the block moves down the slide and off the end of the t

Virty [35]

Answer:

B) d = √ ( 4 h₂ ( H - 2h₂))

Explanation:

A) 1) If the height of the slide is very small, there is no speed to leave the table, therefore do not recreate almost any horizontal distance

2) If the height is very small downwards, it touches the earth a little and the horizon is small,

B) to find an equation for horizontal distance (d)

We must maximize the speed at the bottom of the slide let's use energy

Starting point Higher

Em₀ = U = m g h₁

Final point. Lower (slide bottom)

Emf = K + U = ½ m v² + m gh₂

As there is no friction the energy is conserved

mgh₁ = ½ m v² + mgh₂

v² = 2 g (h₁-h₂)

This is the speed with which the block leaves the table, bone is the horizontal speed (vₓ)

The distance traveled when leaving the table can be searched with kinematics, projectile launch

x = v₀ₓ t

y = $v_{oy}$ t - ½ g t²

The height is the height of the table (y = h₂), as it comes out horizontally the vertical speed is zero

t = √ 2h₂ / g

We substitute in the other equation

d = √ (2g (h₁-h₂)) √ 2h₂ / g

d = √ (4 h₂ (h₁-h₂))

H = h₁ + h₂

h₁ = H -h₂

d = √ ( 4 h₂ ( H - 2h₂))

3 0

3 years ago

Read 2 more answers

Electromagnetic waves, which include light, consist of vibrations of electric and magnetic fields, and they all travel at the sp

Alekssandra [29.7K]

Answer:

2.92682 m

$1.5\times 10^{18}\ Hz$

250000000000 Hz

$2.88462\times 10^{-8}\ m$

0.21126 m

0.12244 m

Explanation:

c = Speed of light = $3\times 10^8\ m/s$

$\lambda$ = Wavelength

f = Frequency

Wavelength is given by

$\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{102.5\times 10^6}\\\Rightarrow \lambda=2.92682\ m$

The wavelength is 2.92682 m

Frequency is given by

$f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{0.2\times 10^{-9}}\\\Rightarrow f=1.5\times 10^{18}\ Hz$

The frequency is $1.5\times 10^{18}\ Hz$

$f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{1.2\times 10^{-3}}\\\Rightarrow f=250000000000\ Hz$

The frequency is 250000000000 Hz

$\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{1.04\times 10^{16}}\\\Rightarrow \lambda=2.88462\times 10^{-8}\ m$

The wavelength is $2.88462\times 10^{-8}\ m$

$\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{1.42\times 10^{9}}\\\Rightarrow \lambda=0.21126\ m$

The wavelength is 0.21126 m

$\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{2.45\times 10^9}\\\Rightarrow \lambda=0.12244\ m$

The wavelength is 0.12244 m

8 0

3 years ago

How do you solve this

Verdich [7]

Answer:

The answer is C

Explanation:

The radius is HALF of the diameter...so you would have to find a dividing "2". :)

8 0

4 years ago

Read 2 more answers