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3 years ago

8

The amount of energy the body uses when at rest is referred to as _____.

1 answer:

Nesterboy [21]3 years ago

8 0

The answer is Basal Metabolic Rate. It is the total amount of energy expressed in calories that an individual needs to keep the body working at rest. Some of those progressions are blood circulation, breathing, cell growth, controlling body temperature, nerve and brain function, and tightening of muscles.

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Will mark as brainliest if correct!!!!!

irakobra [83]

Refraction refers to C. the bending of light rays when they pass from one medium into another

Explanation:

Refraction is a phenomenon typical of wave. Refraction occurs when a wave travels through the boundary between two different mediums. When this occurs, the wave changes speed, wavelength and direction (but the frequency remains the same).

In particular, the direction of the refracted ray is determined by Snell's Law:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where

$n_1$ is the index of refraction of the 1st medium

$n_2$ is the index of refraction of the 2nd medium

$\theta_1$ is the angle of incidence, which is the angle between the direction of the incident wave and the normal to the boundary

$\theta_2$ is the angle of refraction, which is the angle between the direction of the refracted wave and the normal to the boundary

Therefore, the correct description of refraction is

C. the bending of light rays when they pass from one medium into another

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

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egoroff_w [7]

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What power of an engine is required to pump 2450N of water per second from a well 50m deep to the surface

Arisa [49]

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Jobisdone [24]

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rigt on ur mom

*death

6 0

3 years ago

Read 2 more answers

If the train can slow down at a rate of 0.625 m/s2, how long, in seconds, does it take to come to a stop from this velocity?

qwelly [4]

Answer:

66.28 s

Explanation:

Step 1:

Acceleration,a= $0.065m/s^2$

Time,t=9.75 min= $9.75\times 60=585s$

1 min=60 s

Initial velocity,u= $3.4m/s$

We have to find the final velocity of train.

We know that

$v=u+at$

Substitute the values

$v=3.4+0.065(585)=41.425m/s$

Step 2:

Now, initial velocity,u=41.425m/s

Deceleration,a= $-0.625m/s^2$

Because the train velocity decreases

Final velocity, v=0

Again, substitute the values in the above formula

$0-41.425=-0.625t$

$-41.425=-0.625t$

$t=\frac{-41.425}{-0.625}$

$t=66.28s$

Hence, the train takes 66.28 s to come to stop from velocity 41.425m/s.

6 0

3 years ago