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3 years ago

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Two straight wires carry current of 5A opposite direction separated by a distance of 30cm. What is the magnitude of magnetic fie

ld at point P exactly the middle of them 15cm from each wire

1 answer:

jek_recluse [69]3 years ago

6 0

Answer:

The magnitude of magnetic field of both wires is β= 13. 33 $x10^{-6}$ T

Explanation:

$p=15cm*\frac{1m}{100cm}=0.15m$

$I=5A$

$u_{o} = 4*\pi x10^{-7}$

Using the right hand rule field magnetic as the current go in opposite direction the field in the point exactly in the middle have the same direction both so

$\beta _{t} =\beta _{1}+\beta _{2}$

They have the same direction and the P point is the middle as the same current field can be find:

$\beta _{t} =\beta _{1}*2$

$\beta = \frac{u_{o}*I }{2*\pi *p} \\\beta =\frac{4*\pi x10^{-7}*5A }{2*\pi *\frac{30}{2} } \\\beta =\frac{4x10^{-7}*5 }{0.30} \\\beta =6.6x10^{-6}$ T

$\beta _{t} =6.6x10^{-6}*2$ =13.33 $x10^{-6}$ T

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See explanation

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Solution:-

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- See diagram (attached) for clarity.

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Answer:

The resultant velocity is 360.5 m/s and direction 79° north of east.

Explanation:

Given that,

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