Answer: -
3.3° C
Explanation: -
Mass of water m = 180.5 g
Energy released as heat Q = 2494 J
Specific heat is defined as the heat required to raise the temperature of the unit mass of a given substance by 1 C.
Specific heat of water Cp = 4.184 (J/g)⋅∘C
Using the formula
Q = m x Cp x ΔT
We get temperature change ΔT = Q / (m x Cp)
= 2494 J / ( 180.5 g x 4.184 (J/g)⋅∘C
= 3.3° C
Thus the temprature change, (ΔT), of the wateris 3.3 °C if 180.5 g of water sat in the copper pipe from part A, releasing 2494 J of energy to the pipe
The equilibrium vapor pressure of a liquid is the pressure exerted by a vapor on the liquid at a given temperature. It is measured in atm.
Answer:
4 is the actual answer, the other answer can eat my ...
Explanation:
The answer is 100% legit answer choice 4 not 3!!!!!!
This is because the 2260 is 10^2 and then ^3 is increased when boiling a 100 gram
They are called ISOTOPES.
:)
The answer is B as isotopes are different versions of the same chemical element containing the same amount of protons and electrons but different amounts of neutrons.