Answer:
53.4%
Explanation:
N₂ + 3H₂ → 2NH₃
Given that:
26.3 g of H₂ react with N₂ to produce 79.0 g of NH₃
Then:
The number of moles of H₂ = 26.3g of H₂ * (1 mol of H₂/ 2.02g of H₂)
= 13.05 mol of H₂
The number of moles of NH₃ = 13.05 mol of H₂ * ( 2mol of NH₃/ 3 mol of H₂)
= 8.697 mol of NH₃
The mass of NH₃ = 8.697 mol of NH₃ *( 17.04g of NH₃/ 1 mol of NH₃) = 148.1 g of NH₃
The percent yield = actual yield/ theoretical yield * 100%
The percent yield = ( 79.0 g/ 148.1 g )* 100%
The percent yield ≅ 53.4 %
Since the Chlorine gained an electron, it became a chlorine ion with +1 charge. Therefore, it is Cl⁺¹.
Answer:
The answer to your question is : letter B. 0.25 atm
Explanation:
To solve this problem we need to use the combined gas law:
<u>P₁V₁</u> = <u>P₂V₂</u>
T₁ T₂
Data
P1 = 0.99 atm V1 = 2 l T1 = 273K
P2 = ? V2 = 4 l T2 = 137K
Now, the clear P2 from the equation and we get
P2 = P1V1T2 / T1V2
Substitution P2 = (2 x 0.99 x 137)/(273 x 4)
P2 = 271.26 / 1092
Result P2 = 0.248 atm ≈ 0.25 atm
Explanation:
When designing and conducting a scientific experiment then it is necessary to sequentially follows all the steps necessary for the experiment.
Also, it is required to identify independent variables, if any. On the other hand, it is required to address any confounding variables, so that it becomes mentioned the type or number of variables present.
Thus, we can conclude that when designing and conducting a scientific experiment:
- Identify the independent variable.
- Address any confounding variables.
Answer:
Percent yield = 90.9%
Explanation:
Given data:
Mass of CaCO₃ = 50.0 g
Mass of CO₂ produced = 20.0 g
Percent yield = ?
Solution:
Chemical equation:
CaCO₃ → CaO + CO₂
Number of moles of CaCO₃:
Number of moles = mass/molar mass
Number of moles = 50.0 g/ 100.1 g/mol
Number of moles = 0.5 mol
Now we will compare the moles of CO₂ with CaCO₃.
CaCO₃ : CO₂
1 : 1
0.5 : 0.5
Mass of CO₂: Theoretical yield
Mass = number of moles × molar mass
Mass = 0.5 mol × 44 g/mol
Mass = 22 g
Percent yield:
Percent yield = ( actual yield / theoretical yield ) × 100
Percent yield = (20.0 g/ 22.0 g) × 100
Percent yield = 0.909 × 100
Percent yield = 90.9%