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Margaret [11]
2 years ago
10

33. Due to some error in a weighing scale, it shows the following reading when at rest (no weight is placed on it). Neerja measu

red her weight on this scale. The weight shown on the scale was 28 kg. What should she do to find out her correct weight?
(A) Add 2 kg to the weight shown. (B) Subtract 2 kg from the weight shown.
(C) Subtract 28 kg from the weight shown. (D) Add 4 kg to the weight shown
Mathematics
1 answer:
Komok [63]2 years ago
5 0

Answer:

The traditional scale consists of two plates or bowls suspended at equal distances from a fulcrum. One plate holds an object of unknown mass (or weight), while known masses are added to the other plate until static equilibrium is achieved and the plates level off, which happens when the masses on the two plates are equal. The perfect scale rests at neutral. A

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What is the answer of x/14 = 6/21
mafiozo [28]

Answer:

X=84/21

Step-by-step explanation:

X/14=6/21

X=(6/21)(14/1)

X=84/21

7 0
2 years ago
Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer
7 0
2 years ago
in a bag of marbles 1/2 of the marbles have a star on them if 8 marbles have a Star how many total marbles are in the bag​
Step2247 [10]

Answer:

Step-by-step explanation:

8x1/2

8/1 x 1/2

8/2

4

The answer is 4

8 0
3 years ago
Read 2 more answers
PLZZZZ HELP WITH THIS QUESTION
Sauron [17]

A. 1/5 fish

We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5

Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.

So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15       3 ÷ 3 = 1 and 15 ÷ 3 = 5    3/15 = 1/5

1/5 of Mike's fish are damsel fish


B. 2/5 fish

Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.

First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5

Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish

And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5

8 0
2 years ago
In his free time, Gary spends 11 hours per week on the Internet and 11 hours per week playing video games. If Gary has five hour
Tpy6a [65]

Answer:

62.8% OR 0.628

Step-by-step explanation:

11 hours playing video games

11 hours on the Internet

11 + 11 = 22

5 hours of free time each day

7 days in a week

5 x 7 = 35

22/35 hours are spent

That is 0.62857142857 or I just mathmatically rounded to 0.628

0.628 into a fraction is 62.8%

6 0
3 years ago
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