SAMPLE A - <span>pure substance.
</span>SAMPLE B - <span>homogeneous mixture.
</span>SAMPLE C - <span>heterogeneous mixture.
</span>Pure substance - <span>constant composition and properties.</span>
Homogeneous mixture - same uniform appearance and composition.
Heterogeneous mixture - <span>not </span>uniform<span> in composition, two phases (liquid and dust).
</span>
Answer:
CH2- CH3
|
CH3 - CH2 - C - CH - CH2 - CH2 - CH3
| |
CH3 CH3
Explanation:
Heptane
CH3 - CH2 - CH2 - CH2 - CH2 - CH2 - CH3
3 ethyl 3, 4 dimethylheptane
CH2- CH3
|
CH3 - CH2 - C - CH - CH2 - CH2 - CH3
| |
CH3 CH3
Answer:
a and b are correct
Explanation:
This because both are aqueous solutions,therefore, identity of solvent is same that is water.
And because both solutions are non electrolyte they would not ionize in solution, and for the same concentration, the freezing point of both solution would also be same. Since depression in freezing point is a colligative property this means that it depends on number of solute particles not nature of particles
.
Hence answer is that their freezing points and Identity of the solvent shall remain the same.
Answer:
The number of elements in a compound is counted by identifying and counting the chemical symbols represented in the chemical formula
A compound is a substance that is a mixture of more than one elements.
Compounds are made of two or more elements. These elements are represented by their symbols. These symbols can be identified and the number of elements represented by these symbols are counted.
For example, in the compound H_2OH
2
O :
H represents Hydrogen
O represents Oxygen
The elements in Water ( H_2OH
2
O ) are Hydrogen and Oxygen
Therefore, the number of elements in H_2OH
2
O is 2
Also in, NaClNaCl
The elements are Sodium(Na) and Chlorine(Cl)
There are two elements in NaCl
Hence, the number of elements in a compound is counted by identifying and counting the chemical symbols represented in the chemical formula
Learn more here: brainly.com/question/17571315
