Answer:
-1.82 °C
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 33.9 g
- Mass of water (solvent): 578 g = 0.578 kg
- Freezing point depression constant for water (Kb): -1.82 °C/m
Step 2: Calculate the molality of the solution
We will use the following expression.
m = mass of solute / molar mass of solute × kg of solvent
m = 33.9 g / 58.44 g/mol × 0.578 kg
m = 1.00 m
Step 3: Calculate the freezing point depression (ΔT)
The freezing point depression is a colligative property that, for a non-dissociated solute, can be calculated using the following expression:
ΔT = Kb × m
ΔT = -1.82 °C/m × 1.00 m
ΔT = -1.82 °C
The cell model/theory is a big one
the atomic model/theory
Answer:
Molar mass of Na2HPO4=141.96, of Na2HPO4. 12H2O = 358.14: so to get the same 0.4 M: 28.65/358.14*141.96 g, add water until you reach 200ml , dissolve all solid and then filter to make sterile.
Explanation:
Answer:
<h2>The answer is 2.5 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass of object = 10.02 g
density = 4.08 g/mL
The volume of the object is
We have the final answer as
<h3>2.5 mL to one decimal place</h3>
Hope this helps you
Answer:
it is perpendicular to the surfaces that rub together
