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2 years ago

What is the answer to this:magnesium+oxygen

Chemistry

2 answers:

liq [111]2 years ago

8 0

A student balanced the chemical equation Mg + O2 →MgO by writing Mg + O2 → MgO2.

Ludmilka [50]2 years ago

7 0

Answer:

magnesium oxide

Explanation:

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The mobility and carrier density of Al are 12 cm2/Vs and 1.98×1023 cm−3 , respectively. The mobility and carrier density of Cu a

Misha Larkins [42]

Answer:

R aluminium = 2.63x10^-6 Ω*cm

Rcopper = 1.7 x10^-6 Ω*cm

I would use Cu as interconnections in advanced CMOS nodes.

Explanation:

the conductivity formula equals:

σ = n*g*u

n = carrier concentration

u = mobility

g = charge of carrier

The resistivity is equal to:

R = 1/σ

For the aluminium, we have:

g = 1.602x10^-19 C

R = 1/(1.98x10^23 * 1.602x10^-19 * 12 = 2.63x10^-6 Ω*cm

For copper:

R = 1/(8.5x10^22 * 1.602x10^-19 * 43.2) = 1.7 x10^-6 Ω*cm

According to the calculations found for both resistivities, I would use Cu as interconnections in advanced CMOS nodes, since copper has a lower resistivity and therefore, copper conducts electricity better.

8 0

3 years ago

Superstition or science

Mariana [72]

Answer:

superstition

Explanation:

Because its not related to science ,and also telling about future.

3 0

3 years ago

A 0.568-g sample of fertilizer contained nitrogen as ammonium sulfate, . It was analyzed for nitrogen by heating with sodium hyd

Mariulka [41]

Answer:

6.69%

Explanation:

Given that:

Mass of the fertilizer = 0.568 g

The mass of HCl used in titration (45.2 mL of 0.192 M)

= $0.192*\frac{45.2}{1000}* \frac{36.5}{1 \ mole}$

= 0.313 g HCl

The amount of NaOH used for the titration of excess HCl (42.4 mL of 0.133M)

= $\frac{44.3 \ mL * 1.0 \ L}{1000 \ mL} *0.133 \ mole/L$

= 0.0058919 mole of NaOH

From the neutralization reaction; number of moles of HCl is equal with the number of moles of NaOH is needed to complete the neutralization process

Thus; amount of HCl neutralized by 0.0058919 mole of NaOH = 0.0058919 × 36.5 g

= 0.2151 g HCl

From above ; the total amount of HCl used = 0.313 g

The total amount that is used for complete neutralization = 0.2151 g

∴ The amount of HCl reacted with NH₃ = (0.313 - 0.2151)g

= 0.0979 g

We all know that 1 mole of NH₃ = 17.0 g , which requires 1 mole of HCl = 36.5 g

Now; the amount of HCl neutralized by 0.0979 HCl = $\frac{17}{36.5}*0.0979$

= 0.0456 g

Therefore, the mass of nitrogen present in the fertilizer is:

= $0.0456 \ g \ NH_3 * \frac{1 \ mol \ NH_3 }{17.0 \ mol \ of \ NH_3} * \frac{1 \mol \ (NH_4)_2SO_4}{2 \ mol \ NH_3 } * \frac{2 \ mol \ N }{1 \mol \ (NH_4)_2SO_4}* \frac{14.0 g }{1 \ mol \ N}$

= 0.038 g

∴ Mass percentage of Nitrogen in the fertilizer = $\frac{0.038 \ g}{0.568 \ g} * 100$ %

= 6.69%

8 0

4 years ago

Read 2 more answers

Can some one answer my question for physical science for 9th grade

Feliz [49]

where is the question ??? maybe i can help

4 0

4 years ago

Information gathered by a scientist about the toxicity of chemical X and chemical Y showed that they had individual safe limits

timofeeve [1]

Answer:

Synergism

Explanation:

This is an example of Synergism. Synergism is nothing but working out of two medicines together.

Examples of medical synergies are when doctors treat microbial heart infections with ampicillin and Gentamicin and when people with cancer undergo radiation and chemotherapy or more than one chemotherapy drug at a time.

6 0

4 years ago