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olchik [2.2K]
2 years ago
12

In the laboratory you will find three bottles with the following labels:

Physics
1 answer:
alexandr402 [8]2 years ago
4 0

Answer: m

Explanation:

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A bicycle has a mass of 10kg and an acceleration of 2m/s². What is the net force of the bicycle?
kobusy [5.1K]

Answer:

<h3>The answer is 20 N</h3>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

<h3>Force = mass × acceleration</h3>

From the question

mass = 10 kg

acceleration = 2 m/s²

We have

Force = 10 × 2

We have the final answer as

<h3>20 N</h3>

Hope this helps you

4 0
3 years ago
Which one is it?????
antoniya [11.8K]

Answer:ummm

Explanation:

masss

5 0
3 years ago
Read 2 more answers
During a 0.001 s interval while it is between the plates, the change of the momentum of the electron Δp with arrow is &lt; 0, -8
Delvig [45]

Answer:

5.5 x 10^5 N/C

Explanation:

t = 0.001 s

Δp = - 8.8 x 10^-17 kg m /s

Force is equal to the rate of change of momentum.

F = Δp / Δt

F = (8.8 x 10^-17) / 0.001 = 8.8 x 10^-14 N

q = 1.6 x 10^-19 C

Electric field, E = F / q = (8.8 x 10^-14) / (1.6 x 10^-19)

E = 5.5 x 10^5 N/C

8 0
3 years ago
A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
givi [52]

To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. Mathematically it can be described as,

f = f_0 (\frac{v_0}{v_0-v})

Here,

f_0 = Frequency of Source

v_s = Speed of sound

f = Frequency heard before slowing down

f' = Frequency heard after slowing down

v  = Speed of the train before slowing down

So if the speed of the train after slowing down will be v/2, we can do a system equation of 2x2 at the two moments, then,

The first equation is,

f = f_0 (\frac{v_0}{v_0-v})

300 = f_0 (\frac{343}{343-v})

(300*343) - 300v = 343f_0

Now the second expression will be,

f' = f_0 (\frac{v_0}{v_0-v/2})

290 = (343)(\frac{v_0}{343-v/2})

290*343-145v = 343f_0

Dividing the two expression we have,

\frac{(300*343) - 300v}{290*343-145v} = 1

Solving for v, we have,

v = 22.12m/s

Therefore the speed of the train before and after slowing down is 22.12m/s

6 0
2 years ago
Ocean breezes are due to which method of heat transfer?
Ber [7]
Ocean breezes are due to the convection method of heat transfer
8 0
2 years ago
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