Answer:
a) There are 
electrons in a liter of water.
b) The net charge is -53601707,1 C
Explanation:
a) To find out how many electrons are in a liter of water (equivalent to 1000 grams of water), we have to find out how many molecules of water there are and then multiply it by 10 (e- per molecule).
We can find out how many molecules are by finding the number of moles and then multiplying it by Avogadro's number (number of elements per mol):
b) As all electrons have the same charge, in order to find the net charge of those electrons we have to multiply the charge of a single electron by the number of electrons:
An important clarification is that while the net charge may seem huge, water as a whole is a neutral medium, because there are as many protons as there are electrons, and as they have the same charge, the net charge of water is 0.
Answer:
True, check attachment for code
Explanation:
To convert java strings of text to upper or lower case, we can use and inbuilt methods To Uppercase and To lower case.
The first two lines of code will set up a String variable to hold the text "text to change", and then we print it out.
The third line sets of a second String variable called result.
The fourth line is where the conversion is done.
We can compare the string
We can compare one string to another. (When comparing, Java will use the hexadecimal values rather than the letters themselves.) For example, if we wanted to compare the word "Fat" with the word "App" to see which should come first, you can use an inbuilt string method called compareTo.
Check attachment for the code
I will be brief
5. There is no displacement as it didn't move
6. Time cannot go backwards so it cannot be negative
Answer:
2.726472 s more or 1.5874 times more time is taken than 10-lb roast.
Explanation:
Given:
- The cooking time t is related the mass of food m by:
t = m^(2/3)
- Mass of roast 1 m_1 = 20 lb
- Mass of roast 2 m_2 = 10 lb
Find:
how much longer does a 20-lb roast take than a 10-lb roast?
Solution:
- Compute the times for individual roasts using the given relation:
t_1 = (20)^(2/3) = 7.36806 s
t_2 = (10)^(2/3) = 4.641588 s
- Now take a ration of t_1 to t_2, to see how many times more time is taken by massive roast:
t_1 / t_2 = (20 / 10)^(2/3)
- Compute: t_1 / t_2 = 2^(2/3) = 1.5874 s
- Hence, a 20-lb roast takes 1.5874 times more seconds than 10- lb roast.
t_2 - t_1 = 2.726472 s more
Answer:
See below
Explanation:
vf = vo + at subtract vo from both sides
vf - vo = at now divide both sides by t
(vf-vo) / t = a
