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4 years ago

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2 answers:

Olenka [21]4 years ago

6 0

Hi there!
At angle B, the light is refracted at an angle in one direction as it enters the glass. As it exits the glass at angle C, It is refracted at another angle in the opposite direction.
Hope this helps, have a nice day :)

const2013 [10]4 years ago

4 0

the answer is f and a i took the quiz

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One student made the incomplete diagram shown below to represent the relationship between igneous rocks, sediments, sedimentary

Kryger [21]

Answer: Option (C)

Explanation: Rock cycle plays an important role in the alteration of rocks from one form to another.

Igneous rocks when undergoes high temperature and pressure condition, it transforms into a metamorphic rock.
Sedimentary rocks are formed from the sedimentation and consolidation of sediments
Igneous rocks are formed due to the crystallization of magma.

Hence the correct answer is option (C)

3 0

4 years ago

What is the total resistance of a 6 ohm and a 8 ohm resistor connected in series?<br> (1 Point)

Oksanka [162]

Answer:

Total Resistance in circuit is Fourteen Ohms <u>(14 Ω).</u>

<u></u>

Explanation:

How do we know, if the resistors are connected in series, the total resistance is the <u>sum of all the resistors.</u>

(Important: The total resistance can only be added just when the resistors are <u>connected in series</u>)

Then, total resistance (<em>TR </em>) is the sum of all resistors (<em>T1 + T2</em>, in this case)

TR = T1 + T2

According to problem data, we have:

TR = 8 Ω + 6 Ω

TR = 14 Ω

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3 years ago

What is the gravitational force on a 10 kg sled traveling at 3.5 m/s down a track?

Jobisdone [24]

Gravitational force is the weight of the object, therefore weight=mass*gravitational field strength=10*9.8=98N therefore the answer is D

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4 years ago

An unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is 3.00 10-

kirill [66]

Answer:0.478 c

Explanation:

Given

mass of lighter Particle $(m_1)=3\times 10^{-28} kg$

mass of heavier Particle $(m_2)=1.51\times 10^{-27} kg$

speed of lighter particle $(v_1)=0.834 c$

Let speed of heavier particle $=v_2$

and Momentum of the particle is given by

$P=\frac{mv}{\sqrt{1-(\frac{v}{c})^2}}$

$P_1=\frac{m_1v_1}{\sqrt{1-(\frac{v_1}{c})^2}}$

$P_1=\frac{3\times 10^{-28}\times 0.834 c}{\sqrt{1-(\frac{0.834 c}{c})^2}}$

$P_1=8.219\times 10^{-28} kg c$

$P_2=\frac{m_2v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

as momentum is conserved therefore $P_1=P_2$

$8.219\times 10^{-28} kg c=\frac{1.51\times 10^{-27}\times v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

$v_2=0.478 c$

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3 years ago