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Anestetic [448]
3 years ago
14

How is the graph of g(x) =

0)^{2}" align="absmiddle" class="latex-formula"> related to the graph of f(x)= x^{2}
Mathematics
1 answer:
seropon [69]3 years ago
5 0

(x - 10)² is the graph x² by translation of 10 units moved to the right.

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I need help pleeeeease
Shkiper50 [21]

Answer:

5

Step-by-step explanation:

because by solving that the answer comes 5.70

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3 years ago
The equation r=u/st is equivalent to u = rst.<br><br> True<br> False
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False, it would end up being st / r
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3 years ago
Read 2 more answers
The polygons are similar. The area of one polygon is given. Find the area of the other polygon.
Fantom [35]

Answer:

108 ft²

Step-by-step explanation:

For the polygon on the left, we are given the length of one side (3 ft) and the total area (27 ft²). With this information, we can determine the length of the other side - 9 ft. I found this by dividing 27 ft² by 3 ft, giving me the final result of 9 ft.

Next, we have to find the other side of the polygon on the <em>right</em> so we can ultimately determine its area. It looks like there is a scale factor of 2 between the two polygons, since 3 × 2 = 6. We know that the bottom side of the left polygon is 9, so multiplying 9 by 2 should give us the bottom side of the polygon on the right. 9 × 2 = 18.

Now, we have the side lengths for the polygon on the right and can determine its area. What is 6 ft × 18 ft? Well, the answer is 107 ft², and this is the answer to the question.

Hopefully that's helpful! :)

5 0
2 years ago
What is the volume of this shape?
jenyasd209 [6]
Answer:
600 ft cubed
Step-by-step explanation:
Triangle volume formula V = 1/2(l*w*h)
1/2(4*12*9) = 216 ft cubed

Formula for rectangular prism V = (l*w*h)
(4*16*6) = 384 ft cubed

Adding the values: 600 ft
6 0
2 years ago
Greg has an MP3 player called the Jumble. The Jumble randomly selects a song for the user to listen to. Greg's Jumble has 6 clas
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An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or half-moon status because at least 50 percent of its surface was illuminated. In the following nights, the Moon displayed characteristics of waxing gibbous as the light continued to grow across the moon’s surface from right to left. The Moon was nearing closer to the full moon phase on November 14th as only a very small dark shadow was visible on the left side. 
The Moon takes 27.3 days (sidereal month) to complete its actual orbit around the Earth. Like the Sun, the Moon rises in the east and sets in the west each day. 
7 0
3 years ago
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