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The linear equation in slope intercept form for population of Jose's town is y = 320x + 2400.
<u>Solution:</u>
Given, the population of Jose's town in 1995 was 2400 and the population in 2000 was 4000,
Let x represent the number of years since 1995.
We have to write a linear equation, in slope- intercept form, that represents this data.
Now, let the change in population per year be p.
Then, population in a year = population change per year number of years + population in 1995.
⇒population in a year = p x + population in 1995
⇒ population in a year = p x + 2400
Here we have an case that, population in 2000 is 4000
Then, number of years since 1995 = 5
So, 4000 = p 5 + 2400 ⇒ 5p = 4000 – 2400 ⇒ 5p = 1600 ⇒ p = 320
Then, our equation will be population in a year = 320x + 2400
Considering the population in a year as y ⇒ y = 320x + 2400.
Hence, the linear equation in slope intercept form is y = 320x + 2400.
Answer:
\sqrt{6}
Explanation:
From the given diagram,
Hypotenuse sde = x
Opposite side = \sqrt{3}
Using the SOH CAH TOA identity
Sintheta = opposite/hypotenuse
Sin 45 = \sqrt{3}/x
x = \sqrt{3}/sin45
Hence the value of x is \sqrt{6}