For this use the formula:
d = Vo * t - (at^2) / 2
Clearing t:
t = d/(v + 0.5*a)
Replacing:
t = 5 m / (7.2 m/s + 0.5 * (-1.1 m/s²)
Resolving:
t = 5 m / (7.2 m/s + (-0.55 m/s²)
t = 5 m / 6.65 m/s
t = 0.75 s
Result:
The time will be <u>0.75 seconds.</u>
The type of balls that sink are the ones that are quite heavy because they have molecules that are dense inside of them that makes it sink. Hope it helps!!!
Answer:
The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.
hmax = 5740.48 m
Explanation:
This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.
V₀ = 420m/s and θ₀ = 53.0°
So, when the cannonball is fired it has horizontal and vertical components:
V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s
V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s
When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:
Vy = V₀y - g tₐ = 0
tₐ = V₀y/g
tₐ = (335.43m/s)/(9.8m/s²) = 34.23s
Then, the maximum height is reached in the instant tₐ = 34.23s:
h = V₀y tₐ - 1/2g tₐ²
hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²
hmax = 11481.77m - 5741.29m
hmax = 5740.48m
Hello there.
<span>Which of the following scenarios would cause a sound to stop being produced?
</span><span>A. The vibration results in a molecule moving vertically.
</span>
