All categories

2 years ago

The launch speed of a projectile is three times the speed it has at its maximum height.what is the elevation angle at launch?

Physics

1 answer:

Sphinxa [80]2 years ago

6 0

Answer:

Given: a projectile of initial launch velocity(V) and launch angle ∅ and no air resistance. At the maximum height, the projectile would have a zero contribution of speed from the vertical component(Vy) Therefore, if we say Vx=Vcos∅ is the only speed the projectile has at the instant of maximum height then we can replace Vx with 1/5V and write 1/5V=Vcos∅. Solving for the the launch angle ∅, gives Inverse Cos(1/5)=78.5 degrees.

You might be interested in

A third baseman makes a throw to first base 40.5 m away. The ball leaves his hand with a speed of 30.0 m/s at a height of 1.4 m

Ugo [173]

Answer:

When the ball goes to first base it will be 4.23 m high.

Explanation:

Horizontal velocity = 30 cos17.3 = 28.64 m/s

Horizontal displacement = 40.5 m

Time

$t=\frac{40.5}{28.64}=1.41s$

Time to reach the goal posts 40.5 m away = 1.41 seconds

Vertical velocity = 30 sin17.3 = 8.92 m/s

Time to reach the goal posts 40.5 m away = 1.41 seconds

Acceleration = -9.81m/s²

Substituting in s = ut + 0.5at²

s = 8.92 x 1.41 - 0.5 x 9.81 x 1.41²= 2.83 m

Height of throw = 1.4 m

Height traveled by ball = 2.83 m

Total height = 2.83 + 1.4 = 4.23 m

When the ball goes to first base it will be 4.23 m high.

8 0

3 years ago

Which of the following is not the result of nuclear decay.

svlad2 [7]

Answer:it’s c

Explanation:

7 0

3 years ago

sound transfers energy through solid liquid and gas what does ocean waves transfer energy through is it water or water and air a

trapecia [35]

Hears the answer is endocytosis. <span />

7 0

3 years ago

A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result

Over [174]

B) law of conservation of momentum

It states that the total momentum of a system before impact is the same as the total momentum of the system after impact.

In this case total momentum before impact:

10kg*5m/s + 5kg * 0m/s = 50 kg m/s

After Impact:

10kg*0m/s + 5kg*10m/s = 50 kg m/s

You can see the momentum before and after impact is same as 50 kg m/s

Of course we assumed that the first cart stopped after the impact, and there are no energy losses.

7 0

3 years ago

How much force is needed to cause a 15 kilogram bicycle to accelerate at a rate of 10

Anarel [89]

Net force = (mass) x (acceleration)... that’s Newton’s 2nd law of motion.
Net force = (15kg) x (10 m/s squared)
Net force = 150 Newtons.

7 0

3 years ago