Answer: 87500J
Explanation:
Given that,
Power exerted by crane = 3,500 W
Time taken = 25 seconds
work done by crane = ?
Since power is the rate of work done per unit time, then power is workdone by the crane divided by the time taken.
i.e power = work / time
3,500 W = work / 25 seconds
Work = 3500W x 25 seconds
Work = 87500J
Thus, 87500 joules of work was done by the crane.
Answer:
8.83m
Explanation:
Given parameters:
Acceleration = 7.8m/s²
Initial velocity = 0m/s
distance covered = 5m
Unknown:
Final velocity = ?
Solution:
The equation to solve this problem with is given as;
V² = U² + 2aS
V is the final velocity
U is the initial velocity
a is the acceleration
S is the distance
Input the parameters and solve;
V² = 0² + 2 x 7.8 x 5 = 78
V = √78 = 8.83m
Answer:
σ = 1.09 mm
Explanation:
<u>Step 1:</u> Identify the given parameters
rod diameter = 20 mm
stiffness constant (k) = 55 MN/m = 55X10⁶N/m
applied force (f) = 60 KN = 60 X 10³N
young modulus (E) = 200 Gpa = 200 X 10⁹pa
<u>Step 2:</u> calculate length of the rod, L
d = 20-mm = 0.02 m
A = 0.0003 m²
L = 1.14 m
<u>Step 3:</u> calculate the displacement of the rod, σ
σ = 0.00109 m
σ = 1.09 mm
Therefore, the displacement at the end of A is 1.09 mm
Answer: The charges on cation and anion balances each other.
Explanation:
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Thus 
combines with two 
ions to give neutral 
The two possible distances that you might infer your friends swam while the lights were out are 25 m and 75 m.
Answer:
Explanation:
So you have to measure the distance covered by your friend in a time gap of 86 s. And the average velocity is given as 0.29 m/s.
Then as per the mathematical calculation of velocity, distance can be measured as the product of velocity with time interval.
Distance = Velocity × Time Interval
Distance = 0.29 m/s×86 s = 24.94 m.
So based on this calculation, one of the possible distance inferred by you will be 24.94 m.
Another possible distance can be guessed from the statements provided. So if the length of pool is 50 m, then covering halfway in opposite direction to his starting direction means completion of one full length i.e., 50 m and then halfway of that 50 m which is 25m, so totally 50 +25 = 75 m.
So in other way, we can assume that your friend has covered 75 m distance during the light out.
Thus, the two possible distances that you might infer your friends swam while the lights were out are 25 m and 75 m.
