3 years ago

Can you help me on this ?

Mathematics

1 answer:

barxatty [35]3 years ago

7 0

Answer:

what one?

Step-by-step explanation:

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Answer:

Step-by-step explanation:

Given that:

all coins are same;

The same implies that the number of the non-negative integral solution of the equation:

$x_1+x_2+x_3+x_4+x_5 = 35$

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$^{(35+3-1)}C_{5-1} = ^{39}C_4$

(b)

Here all coins are distinct.

So; the number of distribution appears to be an equal number of ways in arranging 35 different objects as well as 5 - 1 - 4 identical objects

i.e.

$= \dfrac{(35+4)!}{4!}$

$= \dfrac{39!}{4!}$

(c)

Here; provided that the coins are the same and each grandchild gets the same.

Then;

$x_1+x_2+x_3+x_4+x_5 = 35$

$x_1 > 0 ; \ \ \ x_1 \ \varepsilon \ Z$

$x_1=x_2=x_3=x_4=x_5$

$5x_1 = 35\\\\ x_1= \dfrac{35}{5} \\ \\ x_1= 7$

Thus, each child will get 7 coins

(d)

Here; we need to divide the 35 coins into 5 groups, this process will be followed by distributing the coin.

The number of ways to group them into 5 groups = $\dfrac{35!}{(7!)^55!}$

Now, distributing them, we have:

$\mathbf{\dfrac{35!}{(7!)^55!} \times 5!= \dfrac{35!}{(7!)^5}}$

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