(16.8 kW) means (16,800 joules/second)
Energy in 1 hour = (1 hour) x (16,800 J/s) x (3,600 s/hour)
Energy = (16,800 x 3,600) J
Energy = 60,480,000 Joules
Energy = 60.48 MJ
Answer:
45000cm2(cuarenta y cinco mil centimetros al cuadrado).
Explanation:
porque el volumes es igual a el área de la base por la altra
Answer:
The magnitude of the induced voltage in the loop is 20 mV.
Explanation:
given;
length of loop, L = 0.43 m
width of loop,w = 0.43 m
velocity of moved loop, v = 0.15m/s
magnetic field strength,B = 0.31 T
To determine the magnitude of the induced voltage in the loop, we apply Faraday's law;
magnitude induced E.M.F = BLv
magnitude induced E.M.F = 0.31 x 0.43 x 0.15 = 0.02 V = 20 mV
Therefore, the magnitude of the induced voltage in the loop is 20 mV.
They are measured in joules, calories, and kilocalories
