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saw5 [17]
3 years ago
7

We will look at an example of a banked curve. In this case the normal force provides the needed radial acceleration. This allows

the vehicle to negotiate the curve without having to rely solely on friction. An engineer proposes to rebuild the curve, banking it so that, at a certain speed v, no friction at all is needed for the car to make the curve. At what angle β should the curve be banked if v = 25 m/s, (56 mi/h) and R=250m?
Physics
1 answer:
Lelu [443]3 years ago
7 0

Answer:

The bank angle \beta\\ = 14.30 degrees

Explanation:

In engineering, banking a curve reduces the centripetal force on the cars as they turn round the bend. this helps prevent them from sliding off the road.

The bank angle can be calculated using the formula:

tan \beta =\frac{v^{2}}{gR}

where v = velocity of the car = 25 m/s

R = radius of the bank = 250 m

g = acceleration due to gravity = 9.81 m/s^{2}

tan \beta =\frac{25^{2}}{9.81 \times 250}

tan\beta =0.25484

\beta = tan^{-1} (0.25484)= 14.30 degrees

There fore, the bank angle is approximately 14 degrees

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Semmy [17]

Answer:

Bone

Explanation:

Diagnostic radiology include the use of non-invasive imaging scans to diagnose a patient.

The voltages used in diagnostic tubes range from roughly 20 kV to 150 kV and thus the highest energies of the X-ray photons range from roughly 20 keV to 150 keV.

The tests and equipment used sometimes involves low doses of radiation to create highly detailed images of an area.

4 0
3 years ago
an empty propane tank dropped from a hot air balloon hits the ground with a speed of 143.8 m/s. from what height was the tank re
vodomira [7]
What you know:
Vi=0m/s
Vf=143.8m/s
A=-9.8m/s
d=???
Use the equation Vf^2=Vi^2+2A(d)
Rearrange to isolate d: d=Vf^2/2A
d=(143.8)^2/2(-9.8)
d=20678.4/-19.6
d=-1055m
The tank was released from a height of 1055m
8 0
3 years ago
A boat has a mass of 4040 kg. Its engines generate a drive force of 4660 N due west, while the wind exerts a force of 880 N due
maxonik [38]

Answer:

Explanation:

Given:

Mass of the boat, m = 4040 kg

The driving force of engine, FB = 4660 N in west = + 4660 N

The force of wind, Fwi = 880 N in east = -880 N

The force of water, Fwa = 1400 N in east = -1400N

Total three forces are acting on the boat

Fnet= Fb+fwi+Fwa

Fnet= 4660 - 880 - 1400

Fnet= +2380N

Acceleration (a) = Force/mass

= 2380/4040

= 0.59m/s2

6 0
3 years ago
Read 2 more answers
If I have a 10 lb ball and a 2 lb ball which
mojhsa [17]

Answer:

It would be the 10 lb ball.

Explanation:

The more that an object weighs, the more force that is needed to accelerate it.

Hope this helped

:)

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3 years ago
A man known as H. M. suffered from _________ after an operation removed portions of his ____________.
slavikrds [6]

Answer: A man known as H.M suffered from <u>epileptic seizures </u>after an operation removed portions of his <u>memory</u>.

.

Explanation:

3 0
3 years ago
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