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saw5 [17]
3 years ago
7

We will look at an example of a banked curve. In this case the normal force provides the needed radial acceleration. This allows

the vehicle to negotiate the curve without having to rely solely on friction. An engineer proposes to rebuild the curve, banking it so that, at a certain speed v, no friction at all is needed for the car to make the curve. At what angle β should the curve be banked if v = 25 m/s, (56 mi/h) and R=250m?
Physics
1 answer:
Lelu [443]3 years ago
7 0

Answer:

The bank angle \beta\\ = 14.30 degrees

Explanation:

In engineering, banking a curve reduces the centripetal force on the cars as they turn round the bend. this helps prevent them from sliding off the road.

The bank angle can be calculated using the formula:

tan \beta =\frac{v^{2}}{gR}

where v = velocity of the car = 25 m/s

R = radius of the bank = 250 m

g = acceleration due to gravity = 9.81 m/s^{2}

tan \beta =\frac{25^{2}}{9.81 \times 250}

tan\beta =0.25484

\beta = tan^{-1} (0.25484)= 14.30 degrees

There fore, the bank angle is approximately 14 degrees

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Answer:

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Explanation:

From the question we are told that

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Generally the path difference of this  waves is mathematically represented as

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              tan \theta  = \frac{L}{D}

     =>     \theta = tan ^{-1} \frac{L}{D}

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Substituting values into the formula for path difference

       y = 0.2 *10^{-3} sin(0.2864)  

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          \Delta \phi = \frac{2 \pi }{\lambda }  * y

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         \Delta \phi = \frac{2 \pi }{400 *10^{-9} }  \ * 9.997*10^{-7}

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         \Delta \phi =5 \pi radians = 5 (180^o)  =  180^o  

the solution is subtracted by 360° in order to get the actual angle

 

             

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