How can a parked car move?

A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to

jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire $=3.7\ MA$

b) Current at the center of the circular coil $=2.48\times 10^{5}\ A$

c) Current near the center of a solenoid $236.8\ A$

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where $B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}$

$\mu=4\pi \times 10^{-7}\ \frac{henry}{m}$

Plugging the values,

Conversion $1\times 10^6 A = 1\ MA$ ,and $2cm=\frac{2}{100}=0.02\ m$

$I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA$

⇒Magnetic Field at the center due to circular coil (at center) is given by, $B=\frac{\mu\times I (N)}{2(a)}$

So $I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A$

⇒Magnetic field due to the long solenoid, $B=\mu\ nI=\mu (\frac{N}{l})I$

Then $I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A$

So the value of current are $3.7 MA$ , $2.48\times 10^{5} A$ and $236.8\ A$ respectively.

8 0

3 years ago

A book is sitting on a table. The book is

Sav [38]

Answer:

65 Newtons

Explanation:

4 0

3 years ago

Read 2 more answers

Define the law of conservation of energy

rusak2 [61]

In physics, the law of conservation of energy states that the totalenergy of an isolated system remains constant—it is said to be conserved over time. Energy can neither be created nor destroyed; rather, it transforms from one form to another.

5 0

3 years ago

Read 2 more answers

You are part of a mission to Mars and have been assigned the task of designing balloons for the purpose of carrying scientific i

melomori [17]

Answer:

The radius of the balloon is R= 0.974 m

Explanation:

Atmospheric density on the surface of mars ρ = 0.0154 kg/m³

Mass density of balloon σ 5 gm/m² = 0.005 kg/m²

Total mass of balloon M = density of balloon* surface area

The balloon is considered as sphere

Surface area of sphere is given by 4π R²

Mass of balloon is M =σ *4πR²

M= (0.005 kg/m²)*(4π R²)

Volume of balloon is given by $\frac{4}{3}$ πR³

Density of atmosphere of mass is given by

ρ = Mass of balloon/volume of balloon

=(0.005 kg/m²)*(4π R²)/ $\frac{4}{3}$ πR³

Re arranging R

R = $\frac{3*0.005 kg/m²}{ 0.0154 kg/m³}$

R = 0.974 m

The radius of the balloon is R= 0.974 m

3 0

4 years ago

You build a solenoid containing 500 windings over a 0.20-m length, with a loop radius of 0.025 m for each winding. the current i

marta [7]

The inductance of a solenoid is given by:
$L= \frac{\mu_0 N^2 A}{l}$
where
$\mu_0$ is the vacuum permeability
N is the number of turns of the solenoid
A is the area of one loop of the solenoid
l is its length

For the solenoid in our problem, N=500, and the radius of one loop is r=0.025 m, so the area of one loop is
$A=\pi r^2 = \pi (0.025 m)^2 = 1.96 \cdot 10^{-3} m^2$
and its length is l=0.20 m

So the inductance of the solenoid is
$L= \frac{(4 \pi \cdot 10^{-7} NA^{-2})(500)^2(1.96 \cdot 10^{-3} m^2)}{ 0.20 m}=3.08 \cdot 10^{-3} H$

4 0

4 years ago