Answer:
58.92 g EDTA
Explanation:
315.1 mL = .3151 L
M = Moles / Liter
.3151 L x <u>0.5 mol EDTA</u> x <u>374 g EDTA</u> = 58.92 g EDTA
1 L EDTA 1 mol EDTA
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The combustion reaction of propane would be expressed as:
C3H8 + 5O2 = 3CO2 + 4H2O
To determine the mass of water that is produced from the given amount of propane, we use the mass of propane and the relation of the substances from the balanced reaction. We do as follows:
moles propane = 22 g C3H8 ( 1 mol / 44.1 g ) = 0.50 mol C3H8
moles H2O = 0.50 mol C3H8 ( 4 mol H2O / 1 mol C3H8) = 2 mol H2O
mass H2O = 2 mol H2O ( 18.02 g / 1 mol ) = 36.04 g H2O
Therefore, the mass of water that is produced from 22 grams of propane would be 36.04 g.
Isabella has a pool that has an area of 678.32 dam² while Taddeo has one of 865.42 m². Which pool has the largest surface area?
Solution :
We know, 1 dam² = 100 m².
So, area of Isabella pool in m² is :
A = 678.32 × 100 m² = 67832 m² .
Therefore, area of Isabella is greater that volume of Taddeo .
Answer:
Given Elements are
- Ferrus(Fe)
- Zinc(Zinc)
- Sodium (Na)
- Copper (Cu)
- Silver(Ag)
<h3>Decreasing Order:-</h3>
Na>Zn>Fe>Cu>Ag
<h3><u>Expla</u><u>nation</u><u>:</u><u>-</u></h3>
- Here is the reactivity series of elements to let you understand better .