A football player kicks the ball with an initial velocity of 28.3 m/s at an angle of 60° above the horizontal. The ball is in th

Question

2 years ago

12

e air for a total of 5.00 s before hitting the ground. Ignoring air resistance, what would be the ball's horizontal displacement?

1 answer:

alexgriva [62] · Answer 1 · 2022-09-24T08:38:28+03:00

Hi there!

Since the ball is directed 60° above the horizontal, we must use its HORIZONTAL component to find its displacement.

We can take the cosine to do so:

vcosθ = 28.3cos(60) = 14.15 m/s

Since the ball is in the air for 5 sec, we can use the following equation:

displacement = velocity · time (d = vt)

Plug in the values:

d = 14.15 · 5 = 70.75 m