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insens350 [35]
3 years ago
14

Two waves with equal amplitude meet each other, resulting in a wave zero amplitude. Which phenomenon explains this result?

Physics
2 answers:
jeka57 [31]3 years ago
4 0

Answer:

(D) Interference

Explanation:

Interference is a phenomenon characteristic for waves. When two waves meet, they interfere and result in a new wave. The precise shape of the resultant wave depends on the amplitude, frequency and phase of the constituent waves. In a most basic setting, two types of interference occur: constructive (resultant amplitude increases) and destructive (resultant amplitude decreases).

Lynna [10]3 years ago
4 0
You answer to this question is D
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You just found a new organism. It is a single cell and has a cell wall but no nucleus. What kind of organism is it. Explain your
andrew11 [14]
The type of organism is an Archaea. Archaea are organisms that have a cell wall but lacks a nucleus. It has a hydrothermal vent which is used to live in high heat areas.
8 0
3 years ago
What is the speed of an object in its rest frame?
Brilliant_brown [7]

Answer:

A. 0 m/s

Explanation:

The rest frame of an object is defined as the reference frame that is moving together with the object, so at the same speed of the object.

In other words, the rest frame of an object is defined as the reference frame in which the object is at rest, which means that is the reference frame in which the object has speed equal to zero (0 m/s).

Therefore, the correct answer is

A. 0 m/s

3 0
3 years ago
Ender and Shen are flying at each other during a battle in space. Ender moves with a velocity v1 of 12 m/s and Shen, with a mass
Shalnov [3]

Answer:

Ender's mass = 2.25 kg

Explanation:

using law of conservation of momentum .

since there is inelastic collision

given.

let \ \ m_{1} =  m \\m_{2} = 45 kg \\v_{1} = 12 m/s \\v_{2} = 9 m/s \\\\V_{3} =6.4 m/s\\using \  \ \\m_{1}v_{1} + m_{2}v_{2} = (m_{1} +m_{2})V\\m\times12 + 45\times9  = (m+45)\times6.4\\64m -12m        = 405 -288\\52m =117\\m =\frac{117}{52}\\m =2.25kg

6 0
3 years ago
A 15 kg block is on a ramp which is inclined at 20o above the horizontal. It is connected by a string to a 19 kg mass which hang
12345 [234]

Answer:

The magnitude of the acceleration of the 19 kg block is 1.414 m/s²

Explanation:

From Newton's second law of motion;

F_{Net} = ma

where;

m is the mass of the objects involved, kg

a is the acceleration of the object, m/s²

different forces on the block and string

⇒force due to 15 kg block

=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396

= 138.12 N

⇒Tensional Force on 19 kg mass:

T = mg = 19×9.8 = 186.2 N

F_{Net} = T-mg = a(m_1+m_2)

186.2 - 138.12 = a(15+19)

48.08 =  a(34)

a = 48.08/34

a = 1.414 m/s²

Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²

7 0
4 years ago
A high-jumper, having just cleared the bar, lands on an air mattress and comes to rest. Had she landed directly on the hard grou
Hoochie [10]

Answer:

e. the air mattress exerts the same impulse, but a smaller net avg force, on the high-jumper than hard-ground.

Explanation:

This is according to the Newton's second law and energy conservation that the force exerted by the hard-ground is more than the force exerted by the mattress.

The hard ground stops the moving mass by its sudden reaction in the opposite direction of impact force whereas the mattress takes a longer time to stop the motion of same mass in a longer time leading to lesser average reaction force.

<u>Mathematical expression for the Newton's second law of motion is given as:</u>

F=\frac{dp}{dt} ............................................(1)

where:

dp = change in momentum

dt = time taken to change the momentum

We know, momentum:

p=m.v

Now, equation (1) becomes:

F=\frac{d(m.v)}{dt}

<em>∵mass is constant at speeds v << c (speed of light)</em>

\therefore F=m.\frac{dv}{dt}

and, \frac{dv}{dt} =a

where: a = acceleration

\Rightarrow F=m.a

also

F\propto \frac{1}{dt}

so, more the time, lesser the force.

<em>& </em><u><em>Impulse:</em></u>

I=F.dt

I=m.a.dt

I=m.\frac{dv}{dt}.dt

I=m.dv=dp

∵Initial velocity and final velocity(=0), of a certain mass is same irrespective of the stopping method.

So, the impulse in both the cases will be same.

4 0
3 years ago
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