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lesantik [10]
3 years ago
10

I just need an example of a Nuclear Process equation where the protons are equal on both sides.

Physics
1 answer:
irina [24]3 years ago
7 0

Answer:

\frac{6}{3}Li+\frac{2}{1}H → 2 \frac{4}{2}He

Explanation:

=)

(the fraction bars are just so  I could put it in)

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Which of the following best describes the location of the
marshall27 [118]

Answer:

The mantle exists above the crust of the earth

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3 years ago
A charge of 5.67 x 10^-18 C is placed 3.5 x 10^-6 m away from another charge of -
Fudgin [204]
+ 1.58 e -15

Please hit thanks button! :)
5 0
2 years ago
A chair of weight 100 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 4
otez555 [7]

Answer:

The normal force will be "122.8 N".

Explanation:

The given values are:

Weight,

W = 100 N

Force,

F = 40 N

Angle,

θ = 35.0°

As we know,

⇒  N=W+FSin \theta

On substituting the given values, we get

⇒      = 100N+40N \ Sin \theta

⇒      =100N+22.8

⇒      =122.8 \ N

7 0
3 years ago
A 250–g piece of gold is at 19 °C. 5.192 kJ of energy is added to it by heat. The specific heat of gold is 129 J/(kg·°C). Calcul
algol [13]

Answer:

A. DT is given by Q= MCs DT

m = mass of the substances

Cs= is it's specific heat capacity

Ck= <u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>Q</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

Mk ×DTk

=<u>2</u><u>5</u><u>0</u><u> </u><u>×</u><u> </u><u>9</u><u> </u><u>×</u><u> </u><u>5</u><u> </u><u> </u>

129

=Dt = 180.1085271

answer is 180degree C.

Explanation:

B. = <u>2</u><u>5</u><u>×</u><u>1</u><u>0</u> ×100

1.082

=<u>2</u><u>5</u><u>0</u><u>0</u>

1.082

= 23105.360 g/kj.

7 0
3 years ago
A bobsled team accelerates the sled to go to 150 m/s in 3 seconds from rest.(a)What is the
Sergeeva-Olga [200]

Answer:

Explanation:

From the equation of Newton's laws of motion

v = u + at where v is final velocity , u is initial velocity and t is time.

150 = 0 + a x 3

a = 50 m / s ²

s = ut + 1/2 at²  ; s is distance travelled

s = 50 x 3 + .5 x 50 x 3²

= 150 + 225

= 375 m .

7 0
3 years ago
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