Answer:
The core. Hope this helps and mark me brainliest <3
Explanation:
Answer:
When calcium reacts with tellurium it will donates its two electrons and these two electron will be accepted by tellurium.
There must be 1 calcium atom for every 1 tellurium atom in the reaction.
Explanation:
Calcium has atomic number of 20. Its electronic configuration is given as:
![[Ca]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2](https://tex.z-dn.net/?f=%5BCa%5D%3D1s%5E2%202s%5E2%202p%5E6%203s%5E2%203p%5E6%204s%5E2)
Calcium atom will loose 2 elections to attain electronic configuration of noble gas.
![[Ca^{2+}]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^0](https://tex.z-dn.net/?f=%5BCa%5E%7B2%2B%7D%5D%3D1s%5E2%202s%5E2%202p%5E6%203s%5E2%203p%5E6%204s%5E0)

Tellurium has atomic number of 52. Its electronic configuration is given as:
![[Te]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4s^24p^6 4d^{10} 5s2 5p4](https://tex.z-dn.net/?f=%5BTe%5D%3D1s%5E2%202s%5E2%202p%5E6%203s%5E2%203p%5E6%204s%5E2%203d%5E%7B10%7D%204s%5E24p%5E6%204d%5E%7B10%7D%205s2%205p4)
Tellurium atom will gain 2 elections to attain electronic configuration of noble gas.
![[Te^{2-}]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4s^24p^6 4d^{10} 5s2 5p6](https://tex.z-dn.net/?f=%5BTe%5E%7B2-%7D%5D%3D1s%5E2%202s%5E2%202p%5E6%203s%5E2%203p%5E6%204s%5E2%203d%5E%7B10%7D%204s%5E24p%5E6%204d%5E%7B10%7D%205s2%205p6)

So, when calcium reacts with tellurium it will donates its two electrons and these two electron will be accepted by tellurium.

There must be 1 calcium atom for every 1 tellurium atom in the reaction.
Answer:
S orbital:spherical
P orbital:dumbbell
D orbital:double dumbbell
F orbital:complex
Explanation:
Answer:
15.14×10⁷ g
Explanation:
Given data:
Number of particles of NaCl = 1.56×10³⁰ particles
Mass of sodium chloride = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ particles
1.56×10³⁰ particles × 1 mol / 6.022 × 10²³ particles
0.259 ×10⁷ mol
Mass in gram:
Mass = number of moles × molar mass
Mass = 0.259 ×10⁷ mol × 58.44 g/mol
Mass = 15.14×10⁷ g