The graph of the function f(x) = (x + 2)(x + 6) is shown
1 answer:
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Drawing the tree diagram of the problem, we see that there are 6 branches for drawing from Urn A, and then 4 branches for each of the 6 branches, for drawing from Urn B.
This means that there are 6*4=24 possible outcomes, which could be listed as
{(1, 1), (1, 2), (1, 3), (1, 4), (2, 1)... (6, 3), (6, 4)},
where the first coordinates represent drawing from urn A, and the second coordinates, drawing from urn B.
(4, 2) is one of these 24, so the probability is 1/24
remark, this problem could also have been solved by the multiplication principle of the probabilities of separate events, that is 1/6 (probability of drawing 4 from Urn A) times 1/4 (probability of drawing 2 from B) = 1/24
Answer: 1/24
This means that there are 6*4=24 possible outcomes, which could be listed as
{(1, 1), (1, 2), (1, 3), (1, 4), (2, 1)... (6, 3), (6, 4)},
where the first coordinates represent drawing from urn A, and the second coordinates, drawing from urn B.
(4, 2) is one of these 24, so the probability is 1/24
remark, this problem could also have been solved by the multiplication principle of the probabilities of separate events, that is 1/6 (probability of drawing 4 from Urn A) times 1/4 (probability of drawing 2 from B) = 1/24
Answer: 1/24
Alright, lets get started.
The given function is :
When we find the domain of any function, we consider the domian is set of input values for which function should remain real and defined.
In this given function , we have not given any points where function seems going undefined.
Hence the domain is : (-∞, +∞) : Answer
Hope it will help :)
Answer:
The correct option is;
∠A ≅ ∠X
Step-by-step explanation:
The given coordinates of the points of triangle ACB are;
A(-4, 4), C(-1, 3), B(-4, 0)
The given coordinates of the points of triangle XYZ are;
X(0, 8), Y(8, 8), Z(6, 2), therefore, we have
The length. l. of segment is given by the following formula;
For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)
For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4
For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2
For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8
For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2
For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10
Therefore;
XY ~ AB, XZ ~ BC, ZY ~ AC
Which gives;
∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z
