f(x) = 5x is linear. Just a straight line with a slope of +5. So if the intervals are both a difference of 1, then the average rate of change will be the same.
f(x2) - f(x1) over x2 - x1. That's the formula for average rate of change.
So for Section A:
f(x) = 5x, (0,1)
[f(1) - f(0)]/(1-0)
= [5(1) - 5(0)]/1
=(5)/1
=5
Do the same for section B and you'll get 5 as well.
I hope this helps you because I have no clue if my answer is right
Option D is correct. The correct option for the recursive formula is 
Given the sequence 10, 14, 18...
The first term is 10, hence
a1 = 10
The previous terms will be 
From the sequence, we can see that <em>4 is being added to the previous term to get the next term</em>. Hence the nth term will be expressed as:
Get the term before the first term 
If n = 1
Hence the correct option for the recursive formula is
Learn more here: brainly.com/question/18233843
To compare the two classes, the Coefficient of Variation (COV) can be used.
The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)
For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)
The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.
Answer:
9/27 or 9 to 27
Step-by-step explanation:
Answer:
( a+b) ( m^2 + n^2)
Step-by-step explanation:
factorise like terms
m^2 ( a + b ) + n^2 ( m^2 + n^2)
then put like terms together put remaining terms in a bracket
( a + b) ( m^2 + n^2 )
