Answer:
-2.80 × 10³ kJ/mol
Explanation:
According to the law of conservation of energy, the sum of the heat absorbed by the bomb calorimeter (Qcal) and the heat released by the combustion of the glucose (Qcomb) is zero.
Qcal + Qcomb = 0
Qcomb = - Qcal [1]
We can calculate the heat absorbed by the bomb calorimeter using the following expression.
Qcal = C × ΔT = 4.30 kJ/°C × (29.51°C - 22.71°C) = 29.2 kJ
where,
C: heat capacity of the calorimeter
ΔT: change in the temperature
From [1],
Qcomb = - Qcal = -29.2 kJ
The internal energy change (ΔU), for the combustion of 1.877 g of glucose (MW 180.16 g/mol) is:
ΔU = -29.2 kJ/1.877 g × 180.16 g/mol = -2.80 × 10³ kJ/mol
1) B and 2) is B thank you!
Answer:
Explanation:
The mole ratio in a balanced equation tells us the number of moles of each reactant needed and how many moles of product will be made.
We are asked to find the mole ratio between A and D for this reaction.
The mole ratio is found by comparing the coefficients, which are the numbers in front of the formulas.
A has a coefficient of 4 and D has a coefficient of 3.
Therefore, the ratio between A and D is:
- 4:3
