Answer:
128 neutrons
Explanation:
<em>How many neutrons are there in 8 molecules of </em>
<em>?</em>
Step 1: Calculate the number of neutrons in 1 atom of F.
The atomic number (z) of F is 9 and its mass number (A) is 19. We can calculate the number of neutrons using the following expression.
n⁰ = A - Z = 19 - 9 = 10
Step 2: Calculate the number of neutrons in 1 molecule of F₂.
1 molecule of F₂ contains 2 atoms of F. The number of neutrons in 1 molecule of F₂ is:
(8 n⁰/1 atom F) × (2 atom F/1 molecule F₂) = 16 n⁰/1 molecule F₂
Step 3: Calculate the number of neutrons in 8 molecules of F₂
8 molecule F₂ × 16 n⁰/1 molecule F₂ = 128 n⁰
Answer: 3.45 L carbon dioxide are produced
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
of particles.
To calculate the moles, we use the equation:
According to stoichiometry :
5 moles of
produce = 3 moles of
Thus 0.257 moles of
will produce=
of
Volume of
Thus 3.45 L carbon dioxide are produced
The melting point for ice is at 32 degrees <span>Fahrenheit or O degrees Celsius.</span>
Answer:
One gallon of octane produces approximately 7000 L of carbon dioxide.
Note:
I believe that the mass of octane should have been given as 2661 g. However, I understand that your instructor probably gave you this problem, so I will use 4000 g for the approximate mass of one gallon of octane. You can rework the problem on your own, substituting the correct masses of octane if you wish.
Step1. You must first determine the number of moles that are in 4000 g of octane, using the molar mass of octane. Step 2. Then you must determine the number of moles of carbon dioxide that can be produced by that number of moles of octane, based on the mole ratio between octane and carbon dioxide in the balanced equation. Step 3. Then use the ideal gas law to determine the volume in liters of carbon dioxide that can be formed.
Answer:

when there is a radical in the denominator, we should rationalize (mutiply the denominator and numerator by the radical) to get rid of the radical in the denominator.