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3 years ago

Catalysts increase reaction rates by lowering the activation energy of a reaction.

Chemistry

2 answers:

Zielflug [23.3K]3 years ago

8 0

That is 100% correct it is A!!!!
Hoped that helped u!
:D

Setler [38]3 years ago

4 0

The answer is true, catalysts increase rates by lowering the activation energy of a reaction. Catalysts lower the reaction energy and so the reaction occurs faster. Enzymes perform the role of biological catalysts. Most metabolic pathways of the body are controlled by enzymes. Enzymes by classification are proteins. <span />

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Which of the following that alcohol may affect your haelth? What the answer

Harman [31]

Answer:

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3 years ago

How is the structure of atoms altered during fission and fusion?

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4 years ago

1. 17.0 grams of xenon hexafluoride is in a solid container. How many milliliters of that gas

BlackZzzverrR [31]

Answer: The volume of gas is 3020 ml

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 821.4 torr = 1.08 atm (760 torr = 1atm)

V = Volume of gas in L = ?

n = number of moles = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{17.0g}{245.28g/mol}=0.069mol$

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $302.7^0C=(302.7+273)K=575.7K$

$V=\frac{nRT}{P}$

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4 0

3 years ago

What is the formula for lead(ii) phosphate?

Solnce55 [7]

Explanation:

Lead(II) phosphate is an ionic compound with chemical formula Pb3(PO4)2. Lead(II) phosphate is a long-lived electronically neutral reagent chemical.[1] Despite limited tests on humans, it has been identified as a carcinogen based on tests on animals conducted by the EPA.[2] Lead(II) phosphate appears as hexagonal, colorless crystals or as a white powder. Lead(II) phosphate is insoluble in water and alcohol but soluble in Nitric acid (HNO3) and has fixed alkali hydroxides. When lead(II) phosphate is heated for decomposition it emits very toxic fumes containing Lead (Pb) and POx.[3]

6 0

2 years ago

An unknown compound was found to have a percent composition as follows: 47.0%, 14.5 carbon, and 38.5 oxygen. What is its empiric

shusha [124]

KCO₂

K₂C₂O₄

Explanation:

Given parameters:

Percent composition:

K = 47%

C = 14.5%

O = 38.5%

Molar mass of compound = 166.22g/mol

Unknown:

Empirical formula of compound = ?

Molecular formula of compound = ?

Solution:

The empirical formula of a compound is its simplest formula. Here is how to solve for it:

K C O

Percent

composition 47 14.5 38.5

Molar mass 39 12 16

Number

of moles 47/39 14.5/12 38.5/16

moles 1.205 1.208 2.4

Dividing

by smallest 1.205/1.205 1.208/1.205 2.4/1.205

1 1 2

Empirical formula KCO₂

Molecular formula

This is the actual combination of the atoms:

Molecular formula = ( empirical formula of KCO₂)ₙ

Molar mass of empirical formula = 39 + 12 + 2(16) = 83g/mol

n factor = $\frac{true molecular mass}{molar mas of empirical formula}$

n factor = $\frac{166.22}{83}$ = 2

Molecular formula of compound = ( KCO₂)₂ = K₂C₂O₄

Learn more:

Empirical formula brainly.com/question/2790794

#learnwithBrainly

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4 years ago