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inysia [295]
3 years ago
8

Catalysts increase reaction rates by lowering the activation energy of a reaction.

Chemistry
2 answers:
Zielflug [23.3K]3 years ago
8 0
That is 100% correct it is A!!!!
Hoped that helped u!
:D
Setler [38]3 years ago
4 0
The answer is true, catalysts increase rates by lowering the activation energy of a reaction. Catalysts lower the reaction energy and so the reaction occurs faster. Enzymes perform the role of biological catalysts. Most metabolic pathways of the body are controlled by enzymes. Enzymes by classification are proteins. <span />
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This type of pure substance contains more than one type of element chemically bonded
Alex787 [66]

Answer:

A. Compounds

Explanation:

Firstly, don't let the word "pure" confuse you; this is pretty much irrelevant to the question.

The key to answering this question lies in "substance" and "more than one type of element chemically bonded."

Something you ought to memorize is that a substance is either an element or compound. Therefore, you can eliminate choices B./C.

Next, use the part of the definition that says "more than one type of element chemically bonded" to conclude that it's a compound. Not only is this the definition of a compound, but the fact that is says <em>more than one type of element</em> should automatically tell you that it is different from just a regular element (Choice D.).

6 0
3 years ago
Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
3 years ago
What percent by mass of aluminum is present in aluminum sulfate ?
xxMikexx [17]
The percent of aluminium of a aluminium sulfate, AI2(SO4)3 is 15.8%.
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3 years ago
H2C=CH2 + H2 решение?​
Sergio039 [100]

Answer:

CH _{3}CH _{3}

Ethane

5 0
2 years ago
What does botanist study? A. Boats<br> B.Matter<br> C. chemicals<br> D. Plants
4vir4ik [10]

What does botanist study?

\implies {\blue {\boxed {\boxed {\purple {\sf {D.\: Plants}}}}}}

\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆

8 0
3 years ago
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