The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.
So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl.
Answer:
It can be removed by acidic chemicals
Explanation:
<h3>
Answer:</h3>
79.8 ml
<h3>
Explanation:</h3>
Boyle's law describes the relationship between pressure and volume when the temperature is constant. For this question, I will be rounding to significant figures.
Boyle's Formula
When describing the relationship between pressure and volume, the formula 
. In this formula, 
is the initial pressure and volume. On the other side, 
is final pressure and volume. So, to find a missing variable you must plug in the values you are given.
Final Volume
Remember when solving this question to remain constant in your units. When we plug in the values we know we are given:
Now, we can multiply the left side
Finally, we can divide by 385 to isolate the final volume
This gives the final volume of 79.8mL.
Answer:
The correct answer is 2.2 mL.
Explanation:
Given:
Average: 2.9 mL
SD: 0.71 mL
We can define a 1 SD range in which the value of volume (in mL) will be comprised:
Volume (mL) = Average ± SD = (2.9 ± 0.7) mL
Maximum value= Average + SD= 2.9 + 0.7 mL = 3.6 mL
Minimum value= Average - SD = 2.9 - 0.7 mL = 2.2 mL
Thus, the minimum value within a 1 SD range of the average is 2.2 mL
